CareerCup

In the current architectures int is 4 bytes long. signed int would be in the range -2^31 to 2^31.
unsigned int would be in the range 0 to 2^32.

I am posting very naive idea to get range of an integer..Hope it will work for all the architectures(16 Bit,32Bit,64Bit)..As we know integer uses 2s Complement..

#include <stdio.h>

int main()
{

register int i=1; // Using Register Storage Class In order to get faster result Still ,It is very Slow

while(1)
{
   if(++i<0) {
     printf("%d to %d",i,i-1 );
     break;
   }
}
return 0;
}

@ashish...can u tell us more about the written round..

@ann this question was asked during interview. and not writtten test...

int stored decimal no. of around
let A = sizeof(int) * 8;
then decimal no range is [-2^A to (2^A - 1)]

there must be a data structure in STL which allows storing decimal no of very very large range using the linked list kind of implementation.

4294967295 max integer that an int can store.

This might help.

#include<iostream>
#include<cstdlib>

using namespace std;

#define MY_SIZEOF(ele) ((unsigned char *)(&ele+1) - (unsigned char *)(&ele))

int main () {
	int a = 6;
	char b = 'c';
	size_t size;
	cout << MY_SIZEOF(a) << endl;
	cout << MY_SIZEOF(b) << endl;
	cout << MY_SIZEOF(size) << endl;
    return 0;
}

int datatype range is : -32768 to +32767
2^range to 2^(range-1)
@ashish tell us more about your interview rounds.