Interview Question Developer Program Engineers


Country: India
Interview Type: In-Person


Comment hidden because of low score. Click to expand.
2
of 2 vote

public reorderString(String inputString)
{
String lower = "";
String upper = "";
int num = 1;
boolean flag = false; //To check if there is no integer
for(int i = 0; i < inputString.size(); i++)
{
if(inputString.charAt(i) == '@') continue;
if(isUpper(inputString.charAt(i)) upper = upper + inputString.charAt(i);
if(isLower(inputString.charAt(i)) lower = lower + inputString.charAt(i);
else num = num * Integer.parseInt(inputString.charAt(i));
}
String output = lower + upper + "@" + num;
return output;
}

- Anonymous on May 09, 2012 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

public class SortString {

	/**
	 * @param args
	 */
	public static void main(String[] args) {
		// TODO Auto-generated method stub
		String string = "aA1Bb8799ddefgffdh789889c2@C3";
		// output should be abcABC@6
		
		String allLowerCaseLetters = "";
		String allUpperCaseLetters = "";
		int sumOfAllInt = 0;
		String specialCharacters = "";

		char[] chars = string.toCharArray();

		for (int i = 0; i < chars.length; i++) {
			if (Character.isDigit(chars[i])) {
				sumOfAllInt = sumOfAllInt
						+ Integer.parseInt(Character.toString(chars[i]));
			} else if (Character.isLowerCase(chars[i])) {
				allLowerCaseLetters = allLowerCaseLetters
						+ Character.toString(chars[i]);
			} else if (Character.isUpperCase(chars[i])) {
				allUpperCaseLetters = allUpperCaseLetters
						+ Character.toString(chars[i]);
			} else {
				specialCharacters = specialCharacters
						+ Character.toString(chars[i]);
			}

		}

		String outputString = allLowerCaseLetters + allUpperCaseLetters
				+ specialCharacters + Integer.toString(sumOfAllInt);

		System.out.println(outputString);

	}

}

- mollymagees on May 23, 2012 | Flag Reply


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