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Adobe Interview Question Developer Program Engineers

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    There is an ant in a cube placed at one corner and you need to find the shortest path to the diagonally opposite corner. The ant can not fly tht is obvious.

    - devsri on July 03, 2012 in India Report Duplicate | Flag
    Adobe Developer Program Engineer

Country: India
Interview Type: In-Person
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7
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Its simple . Just open the cube box . and join the two diagonally opposite corners .
I mean first ant will move to the middle of the opposite side on the same plane from the staring point .
Then from that point , it'll start move to the corner (which lies diagonally opp to the starting point )
Total length covered = a*(5^0.5)

- Barney on July 03, 2012 | Flag Reply
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Can you elaborate it???

- Anonymous on July 03, 2012 | Flag
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Good answer @Barney

The thing will be like this

First ant will reach at the opposite side of the same plane with respect to the corner in which it's right now.
So then distance covered (If A is the length of one side):
X1=A*(5^(.5))/2
Then again he will move in the same way:
X2=A*(5^(.5))/2

So total distance = A*(5^(.5))

- Soham.m17 on July 23, 2012 | Flag
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0
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In case of cube the minimum distance is daignal of the cube but as mention in question that ant cant fly so we will first cover the daignal of the surface in which ant is placed currently then we will cover the edge that is luying to the target corner from the current position

- priyanka on July 03, 2012 | Flag Reply
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Just check the total distance covered . Because as per my illustration , distance covered is a*(5^0.5)

- Barney on July 03, 2012 | Flag
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oh yes answer would be a*(5^0.5)

- Luv on July 03, 2012 | Flag Reply
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a*(5^0.5)

- at on July 03, 2012 | Flag Reply
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a*(5^0.5) it is...

- atul gupta on July 03, 2012 | Flag Reply
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shortest distance would be=diagonal of the surface+edge
diagonal of the surface=sqrt(2)a
edge =a
shortest distance = a(sqrt(2)+1)

- manishsharma16 on July 04, 2012 | Flag Reply
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U r incorrect .

- Barney on July 04, 2012 | Flag
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please explain why?

- Anonymous on July 04, 2012 | Flag
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bbc.co.uk/schools/ks3bitesize/maths/images/net_of_a_cube.gif

this image show the 3D and 2D view of cube. Mark the diagonals and you will get the answer

- Read Fox on August 28, 2012 | Flag
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i am getting : a*( (1+ sq-root(2))/2) + 1) which is definitely less then a a*(5^0.5)

move half distance along the edge parallel to horizontal plane and then hypotenusely(a/sq-root(2)) to the lower corner(which is 'a' distance from the destination) , now calculate.

- Anonymous on July 14, 2012 | Flag Reply
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0
of 0 vote

The above answer is correct

- Anonymous on July 16, 2012 | Flag Reply
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0
of 0 vote

Answer should be 3^0.5 * L
l is length of cube

- Piyush on September 09, 2012 | Flag Reply
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-1
of 1 vote

It would be (2^0.5 +1)*a

- Luv on July 03, 2012 | Flag Reply
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my ans is the shortest one .

- Barney on July 03, 2012 | Flag


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