Siemens Interview Question Software Engineer in Tests




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1
of 1 vote

{
for (int i = ary.Length – 1; i >= 0; i++)
{
int r = rnd.Next(0, i + 1);

int tmp = ary[i];
ary[i] = ary[r];
ary[r] = tmp;
}
}

- amdube on May 18, 2011 | Flag Reply
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1
of 1 vote

you can Collections.Shuffle() method for the purpose
refer this
"stackoverflow[dot]com/questions/7433506/java-program-design-card-shuffler"

- Sumit Ramteke on November 27, 2012 | Flag Reply
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0
of 0 vote

Fisher–Yates shuffle (aka Knuth Shuffle)

measure occurrances of each perumation over a large testcase...

- EveryoneLovesMicrosoft on November 03, 2009 | Flag Reply
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0
of 0 vote

!EXCLUSIVE!
<object width="445" height="364"><param name="movie" value="http://www.youtube.com/v/ibYMAWi_yq8&hl=ru&fs=1&rel=0&color1=0x5d1719&color2=0xcd311b&border=1"></param><param name="allowFullScreen" value="true"></param><param name="allowscriptaccess" value="always"></param><embed src="http://www.youtube.com/v/ibYMAWi_yq8&hl=ru&fs=1&rel=0&color1=0x5d1719&color2=0xcd311b&border=1" type="application/x-shockwave-flash" allowscriptaccess="always" allowfullscreen="true" width="445" height="364"></embed></object>

Наталья Немец – СОН (2009)
<object width="445" height="364"><param name="movie" value="http://www.youtube.com/v/wCmNnBc_42Q&hl=ru&fs=1&rel=0&color1=0x5d1719&color2=0xcd311b&border=1"></param><param name="allowFullScreen" value="true"></param><param name="allowscriptaccess" value="always"></param><embed src="http://www.youtube.com/v/wCmNnBc_42Q&hl=ru&fs=1&rel=0&color1=0x5d1719&color2=0xcd311b&border=1" type="application/x-shockwave-flash" allowscriptaccess="always" allowfullscreen="true" width="445" height="364"></embed></object>

Наталья Немец (feat. Reflex-music) - глаза на песке (NEW 2010)
<object width="445" height="364"><param name="movie" value="http://www.youtube.com/v/gK393sl1_Ck&hl=ru&fs=1&rel=0&color1=0x5d1719&color2=0xcd311b&border=1"></param><param name="allowFullScreen" value="true"></param><param name="allowscriptaccess" value="always"></param><embed src="http://www.youtube.com/v/gK393sl1_Ck&hl=ru&fs=1&rel=0&color1=0x5d1719&color2=0xcd311b&border=1" type="application/x-shockwave-flash" allowscriptaccess="always" allowfullscreen="true" width="445" height="364"></embed></object>

<object width="445" height="364"><param name="movie" value="http://www.youtube.com/v/ZoskxqgsXVY&hl=ru&fs=1&rel=0&color1=0x5d1719&color2=0xcd311b&border=1"></param><param name="allowFullScreen" value="true"></param><param name="allowscriptaccess" value="always"></param><embed src="http://www.youtube.com/v/ZoskxqgsXVY&hl=ru&fs=1&rel=0&color1=0x5d1719&color2=0xcd311b&border=1" type="application/x-shockwave-flash" allowscriptaccess="always" allowfullscreen="true" width="445" height="364"></embed></object>
sDF

- sdfd on November 03, 2009 | Flag Reply
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0
of 0 vote

Suppose an array of 52 elements represents of a deck of card.
iterate thru each element in the array.
for each element, use a random function to generate an integer from 0-51.
swap the contents of current element with the element at random number generated index.
that's all.

To test it, we need to make sure there are no consecutive elements in the array.

- Girish on November 04, 2009 | Flag Reply
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0
of 0 votes

Can you do better Don? It is much more productive to show your recommendation than to criticize another's.

- M on February 23, 2011 | Flag
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0
of 0 vote

{Can you write a code for this}

- my name on July 14, 2010 | Flag Reply
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0
of 0 vote

DeckOfCards.h:

#pragma once

#include <string>
using std::string;

class DeckOfCards
{
public:
	DeckOfCards(void);
	~DeckOfCards(void);
	void shuffleCards();
	void printDeck();
private:
	const static short CARDS_PER_DECK = 52;
	const static short CONTENT_COUNT = 13;
	const static short TYPE_COUNT = 4;

	enum Content { ONE = 0, TWO, THREE, FOUR, FIVE, SIX, SEVEN, EIGHT, NINE, TEN, JACKS, QUEENS, KINGS};
	enum Type {SPADES = 0, HEARTS, DIAMONDS, CLUBS};
	
	static const char* toString(Content pContent);
	static const char* toString(Type pType);
	struct card {
		Content content;
		Type type;

	private:
		string contToString(){
		switch (content){
			case 0:
				return "ONE";
			case 1:
				return "TWO";
			case 2:
				return "THREE";
			case 3:
				return "FOUR";
			case 4:
				return "FIVE";
			case 5:
				return "SIX";
			case 6:
				return "SEVEN";
			case 7:
				return "EIGHT";
			case 8:
				return "NINE";
			case 9:
				return "TEN";
			case 10:
				return "JACKS"; 
			case 11:
				return "QUEENS";
			case 12:
				return "KINGS";
			default:
				return 0;
			}
		}

		string typeToString(){
			switch (type){
				case 0:
					return "SPADES";
				case 1:
					return "HEARTS";
				case 2:
					return "DIAMONDS";
				case 3:
					return "CLUBS";
				default:
					return 0;
			}
		}
	public:
		string toString(){
			string lTemp(contToString());
			lTemp.append(" of ");
			lTemp.append(typeToString());
			return lTemp;
		}
	};
	card deck[CARDS_PER_DECK];
};

DeckOfCards.cpp:

#include "DeckOfCards.h"

#include <cstdlib>
using std::rand;

#include <ctime>
using std::time;

#include <iostream>
using std::cout;
using std::endl;

DeckOfCards::DeckOfCards(void)
{
}

DeckOfCards::~DeckOfCards(void)
{
}

void DeckOfCards::shuffleCards(){
	srand(static_cast<unsigned int> (time(0)));
	card *lCard = new card();
	for(int i = 0; i < CARDS_PER_DECK; i++){
		lCard->content = Content(rand() % CONTENT_COUNT);
		lCard->type = Type(rand() % TYPE_COUNT);
		deck[i] = *lCard;
		lCard = new card();
	}
}

void DeckOfCards::printDeck(){
	for(int i = 0; i < CARDS_PER_DECK; i++){
		cout << "Card[" << i << "]: " << deck[i].toString() << endl;
	}

}}
Than you just call shuffleCards() and printDeck()...

- Johnny on March 17, 2012 | Flag Reply


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