Microsoft Interview Question Software Engineer / Developers




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of 0 vote

use atoi :)

- anonymous on November 22, 2009 | Flag Reply
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of 0 vote

hfrom vijayinterviewquestions.blogspot.com/2007/07/write-your-own-c-program-to-implement.html

// atoi
// precondition: a string ("1234")
// postcondition: a number converted from the input string
// special case: if a string is too long, the converted number could be bigger than 2^32-1 ?
int myatoi (char* string)
{
int sign = 1;
// how many characters in the string
int length = strlen(string);

// handle sign
if (string[0] == '-')
{
sign = -1;
i = 1;
}

for (i; i < length; i++)
{
// handle the decimal place if there is one
if (string[i] == '.')
break;
number = number * 10 + (string[i]- 48);
}

number *= sign;

return number;
}

- Vaishnavi on November 26, 2009 | Flag Reply
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of 0 vote

Above Program takes care of
1. Sign of the number
2. Number augmentation

but do not handle the negative scenario when the integer in string format contains integer which is overflowing the integer type.

- Check the number after augmenting the number
if( number <0){
throw new OverflowException();
}

- Operation number = number * 10 + (string[i]- 48); can be replaced with
number = number<<3 + number>>1 + (string[i]- 48);

- Ankush Bindlish on November 27, 2009 | Flag Reply
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of 0 vote

static int GetInt(string input)
        {
            int result = 0;
            int mul = (int)Math.Pow(10, input.Length -1);
            foreach (char c in input)
            {
                int n = c - 48;
                result = result + n * mul;
                mul = mul / 10;
            }
            return result;
        }

- sam on September 22, 2013 | Flag Reply


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