CareerCup

// n = 8 
	int calculateChessBoardSquares(int n) {
		int result = 0;
		for(int i=1; i<=n; i++) {
			result += i * i;
		}
		return result;
	}

       // formula for calculating sum: n^3/3 + n^2/2 + n/6
       int calculateChessBoardSquaresWithoutLoop(int n)    {
           return Math.Pow(n,3)/3 + Math.Pow(n,2)/2 + n/6
       }

private static int count(int n) {
		if (n == 1) {
			return 1;
		}
		
		if (n == 0) {
			return 0;
		}
		
		return n * n + count(n -1); 
	}

C#:

void foo(int size){
int answer = 0;

for (int i = 1; i <= size; i++)
	answer += (i*i)

Console.Write(answer);

int squaresInaChess(int n)
{
   int sq = sqrt((double)n);
   int max = 0;
   int cur = 0;

   for (int i = 0; i < sq; i++)
   {
      for (int j = 0; j < sq; j++)
      {
         if (i == j)
            max = i + 1;


         if (max > (j+1))
         {
            cur = cur + (j + 1);
         }
         else
         {
            cur += max;
         }

      }
   }
   return cur;
}

Alternate Answer:
If the input is number of sides "n" in the board, answer would be:
- Iterate from n to 1
- Cumulative sum of squares of each would be number of squares.

For example: if n = 8,
number of squares = 64+49+36+25+16+9+4+1 = 204

private static int count(int n) {
		if (n == 1) {
			return 1;
		}
		
		if (n == 0) {
			return 0;
		}
		
		return n * n + count(n -1); 
	}

private static int count(int n) {
		if (n == 1) {
			return 1;
		}
		
		if (n == 0) {
			return 0;
		}
		
		return n * n + count(n -1); 
	}

private static int count(int n) {
		if (n == 1) {
			return 1;
		}
		
		if (n == 0) {
			return 0;
		}
		
		return n * n + count(n -1); 
	}

Well assuming that you are getting a matrix of colors for example you'll need to only care about the red and black colors.

public static int CalculateSquares(Color[][] board)
{
	Color prev = Color.White;

	int xCount = 0;
	for(int i = 0;i < board.Length; i++)
	{
		Color cur = board[i][0];
		if(cur != prev && (cur == Color.Black || cur == Color.Red))
		{
			xCount++;
		}
	}

	prev = Color.White;
	int yCount = 0;
	for(int i = 0;i < board[0].Length; i++)
	{
		Color cur = board[0][i];
		if(cur != prev && (cur == Color.Black || cur == Color.Red))
		{
			yCount++;
		}
	}

	return xCount*yCount;
}

public class ChessBoard {
public static void main(String[] args){
int n=8;
int sum=0;
for(int i=1;i<=8;i++){
sum=sum+(n-i+1)*(n-i+1);
}
System.out.println("Number of squares in a chessboard are: "+sum);
}
}