CareerCup

Q.1 Rather than separate T[1…m] into two half size arrays for the purpose of merge sorting, we
might choose to separate it into three arrays of size x%3, (x+1)%3, and (x+2)%3, to sort each of
these recursively, and them to merge the three sorted arrays. Give a more formal description of
this algorithm and analyze its execution time. Justify your answer with example.

rain strikes and the roads are flooded .Mr x has to get home from work.your task is to make sure he returns home in the shortest time .consider the roads as a graph with crossing as nodes and the path between two nodes as an edge. SAssume the graph is unidirected and the numbers are numbered .1 to v(v<=50)

Given a square (n x n) matrix which only contains 0 and
1. Find the minimum cost to reach from left most column to rightmost column.
Constraints/rules:
a. Starting point: You can start from any cell in the left most column i.e. (i, 0) where i can be between 0 and n( number of rows/ columns)
b. Destination: You can reach any cell in the rightmost column i. e ( k, n) where k can be anything between 0 and n.
c. You cannot visit a cell marked with 0.
d. Cost is defined as the sum of cells visited in path.
e. You can move up, down, left and right but not diagonally.

For example,
take 2x2 matrix
1 | 0
1 | 1

One possible path is 00 -- 10 -- 11 with cost 3
Other one is 10 -- 11 with cost 2
so minimum cost on this case is 2.

A dictionary is combination of characters from a-z. let's say a=1,b=2.. and so on z=26. you are given n and k. you have to find sum of length k from given combination.
for example n=51 and k=3 then your answer should be =axz
as there can be many combination for given sum so it is suggested to print those string which comes first in dictonary

beautiful numbers are those numbers which contains digit only 4 and 5 also they are palindrome.length of number can't be odd. for example
44,55,4554 are beautiful numbers where as 38, 444 are not.
your task is to find nth number in this series. let's say if n=4 then output should be 4554. for n=1 output will be 44 always.

How can you read last 10 lines of a big file and a follow up question was how would you extend this process optimally to read last 10 lines of 1000s of files?

You are required to collect N numbers from a bag. Initially, the bag is empty. Whenever you put a number X in the bag, then the owner of the bag asks the question.

The questions are as follows:

. What is the greatest integer that is smaller than X and present inside the bag?

. What is the smallest number that is greater than X and present inside the bag?

If you answer both the questions correctly, then you can put X inside the bag. Your task is to answers the questions that are asked by the owner of the bag. If no such numbers exist in the bag print -1.



Example:
5 (Number of elements in the bag)
1
4
2
3
7


output:
-1 -1
1 -1
1 4
2 4
4 -1

given array and max element in array. Find no. of elements present between a given range in O(1). You can do one time processing of array.

Given an integer 'n', create an array such that each value is repeated twice. For example

n = 3 --> [1,1,2,2,3,3]
n = 4 --> [1,1,2,2,3,3,4,4]

After creating it, find a permutation such that each number is spaced in such a way, they are at a "their value" distance from the second occurrence of the same number.

For example: n = 3 --> This is the array - [1,1,2,2,3,3]

Your output should be [3,1,2,1,3,2]

The second 3 is 3 digits away from the first 3.
The second 2 is 2 digits away from the first 2.
The second 1 is 1 digit away from the first 1.

Return any 1 permutation if it exists. Empty array if no permutation exists.

Follow up: Return all possible permutations.

Write a program to find the given new program can be scheduled or not?
Already scheduled Programs: P1(10,5), P2(25,15)
New Programs: P3(18,7), P4(12, 10).
In P1(10, 5), where 10 is the starting time, 5 is the execution time.
As The P3(18, 7) starts at time 18 and executes for 7 mins i.e., the end time is 18+7 = 25. So this time slot is free and there is no overlap with already scheduled programs. Hence P3 can be scheduled.

As the P4 overlaps with P1, So P4 cannot be scheduled.

Given two strings, A and B, of equal length, find whether it is possible to cut both strings at a common point such that the first part of A and the second part of B form a palindrome.

Extension1. How would you change your solution if the strings could be cut at any point (not just a common point)?

Extension2. Multiple cuts in the strings (substrings to form a palindrome)? Form a palindrome using a substring from both strings. What is its time complexity?

Write a new data structure, "Dictionary with Last"

Methods:
set(key, value) - adds an element to the dictionary
get(key) - returns the element
delete(key) - removes the element
last() - returns the last key that was added or read.

In case a key was removed, last will return the previous key in order.

Prroblem: write an algorithm to calculate the minimum cost to add new roads between the cities such that all the cities are accessible from each other

int numTotalAvailableCities = 6;
int numTotalAvailableRoads = 3;
int[,] roadsAvailable = { { 1, 4 }, { 4, 5 }, { 2, 3 } };
int[,] costNewRoadsToConstruct = { { 1, 2,5 }, { 1,3,10 }, {1,6,2} ,{ 5, 6, 5 } };
int numNewRoadsConstruct = 4;

public class MinimumCostToConstructNewRoad
    {
        public static int getMinimumCostToConstruct(int numTotalAvailableCities,
            int numTotalAvailableRoads,
            int[,] roadsAvailable,
            int numNewRoadsConstruct,
            int[,] costNewRoadsConstruct)

        {
            int totalCost = 0;
            bool[] Visited = new bool[numTotalAvailableCities];
            int[] Keys = new int[numTotalAvailableCities];
            int[] Parent = new int[numTotalAvailableCities];

            int[,] AdjMatrix = GetAdjecencyMatrix(roadsAvailable, costNewRoadsConstruct, numTotalAvailableCities);


            for (int i=0;i< numTotalAvailableCities;i++)
            {
                Keys[i] = Int32.MaxValue;
            }

            Keys[0] = 0;
            Parent[0] = -1;

            for(int i=0;i< numTotalAvailableCities-1;i++)
            {
                var u = FindMin(Visited, Keys);

                Visited[u] = true;
                for(int v=0;v< numTotalAvailableCities;v++)
                {
                    if(Visited[v]==false && AdjMatrix[u, v]!=Int32.MaxValue && AdjMatrix[u,v]<Keys[v])
                    {
                        Parent[v] = u;
                        Keys[v] = AdjMatrix[u, v];
                    }
                }

            }

           for(int i=1;i< numTotalAvailableCities;i++)
            {
                totalCost = totalCost + AdjMatrix[Parent[i], i];
            }
            return totalCost;
        }


        private static int FindMin(bool[] Visited, int[] Keys)
        {
            int min = Int32.MaxValue; int index = -1;
            for (int i = 0; i < Keys.Length; i++)
            {
                if (Visited[i] == false && Keys[i] < min)
                {
                    min = Keys[i];
                    index = i;
                }
            }
            return index;
        }


        private static int[,]  GetAdjecencyMatrix(int[,] roadsAvailable, int[,] costNewRoadsConstruct,int numTotalAvailableCities)
        {
            int[,] AdjMatrix = new int[numTotalAvailableCities, numTotalAvailableCities];

            for (int i = 0; i < numTotalAvailableCities; i++)
            {
                for (int j = 0; j < numTotalAvailableCities; j++)
                {
                    AdjMatrix[i, j] = Int32.MaxValue;
                }
            }


            int count = 0;
            for (int i = 0; i < roadsAvailable.GetLength(0); i++)
            {
                int start = roadsAvailable[i, count]-1;
                int end = roadsAvailable[i,count+1]-1;
                AdjMatrix[start, end] = 0;
            }

            for (int i = 0; i < costNewRoadsConstruct.GetLength(0); i++)
            {
                int start = costNewRoadsConstruct[i, count]-1;
                int end = costNewRoadsConstruct[i, count+1]-1;
                int cost= costNewRoadsConstruct[i, count + 2];

                AdjMatrix[start, end] = cost;
            }

            return AdjMatrix;
        }
    }

Given a string s contains lowercase alphabet, find the length of the Longest common Prefix of all substrings in O(n)

For example

s = 'ababac'

Then substrings are as follow:

1: s(1, 6) = ababac
2: s(2, 6) = babac
3: s(3, 6) = abac
4: s(4, 6) = bac
5: s(5, 6) = ac
6: s(6, 6) = c

Now, The lengths of LCP of all substrings are as follow

1: len(LCP(s(1, 6), s)) = 6
2: len(LCP(s(2, 6), s)) = 0
3: len(LCP(s(3, 6), s)) = 3
4: len(LCP(s(4, 6), s)) = 0
5: len(LCP(s(5, 6), s)) = 1
6: len(LCP(s(6, 6), s)) = 0

String contains only lowercase alphabates.

Implement phone book <unique name, number>
1.Sorted phone book
2.searching based on name
3Searching based on number. What are the data strutures required

How should I prepare for the interview with Alexa team at Amazon?

If you had n racers and m checkpoints, how would you list out the racers in the order in which they are in the race given that each checkpoint gets a notification when a specific racer crosses it?

Your code should run in O(1).

Note: Players cannot cheat, i.e. they cannot miss a checkpoint

Example:

Assume 5 checkpoints(C1, C2, C3, C4, C5) and 10 racers(P1, P2,...P10).

Now once the race begins, lets say P2 first crosses C1. So the current race order is P2.

Now P1, P3, P4 cross C1; so the race order is P2, P1, P3, P4.

Now P1, crosses C2; so the race order becomes P1, P2, P3, P4

Now P3, crosses C2; so the race order becomes P1, P3, P2, P4

Now P5, crosses C1; so the race order becomes P1, P3, P2, P4, P5

Now P1 crosses C3; so the race order remains P1, P3, P2, P4, P5

and so on.

Assume that you get notified of players crossing a checkpoint by a function update(player name, checkpoint). Your task is to show the players in order in O(1) i.e return a vector of players in-order in O(1)

Given multiple input streams of sorted numbers of infinite size, produce a single sorted output stream.

(The size of all the input streams are unknown)

For eg.

Input Stream 1: 2,4,5,6,7,8...........
Input Stream 2: 1,3,9,12..............
Input Stream 3: 10,11,13,14........

Output Stream:
1,2,3,4,5,6,7,8,9,10,11,12,13...............

print hockey stick number in pascal triangle where row of triangle can be upto 30000 and length of stick can be upto 100.

Question : Given a set of N numbers [1,N], partition them into 2 disjoint subsets based on a set of K queries.
Each query is of the type (n1, n2) where n1 and n2 are distinct numbers from the set and n1 and n2
belong to opposite subsets.

Example:

Input:

Input:
N = 4
K = [(1, 2), (1, 3), (2, 4)]

Output:
Set 1 : (1,4)
Set 2 : (2,3)

word look up

You have been given a map which holds book name and book author. One author might have several different books. But books are unique. Now, write a function which will return you a Map which will have the author name as unique and all the books he has written as values.

Book Map=["Java"-->"John", "C#"-->"Rob", "Ruby"-->"John", "Rails"-->"Rob"]

This should return a Map which has the following:

["John"-->{"Java","Ruby"}
"Rob"--{"C#","Rails"}]

https://codejamanalysis.wordpress.com/2017/03/18/crossover-problem-super-stack/

Any Optimized Solution to avoid TLE for 4 test cases. I have tried by implementing Stack using Doubly Linked List.
Still not able to pass test cases!!!

Given a BST of memory sizes. Find best fit for a memory block of size M.

Given a wall, which is made up of two types of bricks (Porus / opaque ). Porus bricks allow water pass through them. Opaque won't. Find whether water reaches to ground, if there is any rainfall.
Water can flow from top to bottom, diagonally, horizontally as well. Only flowing from bottom to top is not possible.

Given a 2-d integer array, find the size of the largest connected area (number of elements connected), where two elements are connected if they are side-adjacent in matrix(up,down,left,right operations). Also there can be maximum of two different integers present in this set.

We have an array if 0's and 1's like

00010000010001001

Assume that all 1's are a person and if a new person comes and if we want to add to the array in such a way that the gap between individuals are maximum as possible.

if we add a new person, then the new array should be

000100100010001001

Given a string as input, return the list of all the patterns possible:

'1' : ['A', 'B', 'C'], 
'2' : ['D', 'E'],
'12' : ['X']
'3' : ['P', 'Q']

Example if input is '123', then output should be [ADP, ADQ, AEP, AEQ, BDP, BDQ, BEP, BEQ, CDP, CDQ, CEP, CEQ, XP, XQ]

/*Coding question: The customers for a particular business, required to use a webpage to select a Browse Node.
A Browse Node, is an element in the classification structure used to classify products in the Amazon webpage.
The products are classified in 8 categories. Each category has its own sub-classification that looks like a tree with many
children per node and many levels. The UI developer has a tool to paint such tree. He requires from you (You are the backend developer)
to implement 2 interfaces for him:

Node getRoot();
List<Node> getChildren(Node node);
The data is available for you in a text file with this format:
//nodeid, parent_node_id, nodename

Example:
//nodeid, parent_node_id, nodename
10, 1, Comedy Books
20, 2, Tablets
1, -1, Books
11, 1, Novels
12, 11, Terror novels
2, -1, Electronics
-1, 0, GlobalRoot
*/

Given n line segments, find if any two segments intersect
http://www.geeksforgeeks.org/given-a-set-of-line-segments-find-if-any-two-segments-intersect/