CareerCup

Java:

public static void main(String[] args) {
	for (int i=1; i<7; i++) {
		for(int j=0; j<i; j++){
			System.out.print("*");
		}
		System.out.println();
	}
}

i don't think u need so many loops to do that

void printpattern(int num) {
       char *stars = "*";
       int i = 0;
       for(i=0;i<num;++i) {
          printf("%s\n%s\n", stars, stars);
          strcat(stars,"*");
       }
       return;
}

yeah i agree, i want to just give an idea.For doing this simpler.
We can print recursively without using loops.

heres another solution:

void printStars(int n) {
char stars[n+1];
for(int j = 0;j < n; j++) {
stars[j] = '*';
stars[j+1] = '\0';
cout<<"\n"<<stars<<"\n"<<stars;
}
}

public static void printStarList( int n)
    for(int i=0;i<n;i++) {
     if ( (i % 2)==0 ) {
       printNStats(i/2);
      }
     else if ( (i%2) ==1 ) {
       printNStats(i/2+1);
    }  
    }

void printpattern(int num)
{
char *stars = "*";
char *starsnew;
int i = 0;
for(i=0;i<num;++i)
{
printf("%s\n%s\n", stars, stars);
starsnew = (char*)malloc(sizeof(*stars) + 1);
strcat(starsnew , stars);
strcat(starsnew,"*");
stars =starsnew;
}
return ;
}

Here's Python:

def printpattern(n):
    [print(2*(i*'*' + '\n'), end='') for i in range(1,n+1)]
printpattern(5)