CareerCup

suppose `hour' is in [0..11]
and `min' is in [0..59]
we do not take seconds into account for simplicity

compute_angle(int hour, int min) {
   float ha = (float)(hour + min / 60.0f) * 360 / 12.0f; // position of hours hand
   float ma = (float)min * 360 / 60.0f; // position of minutes hand
   float a = std::abs(ha - ma);
   if(a > 180)
       a = 360 - a;
   return a; // return the angle difference
}

find the angle bvetween the hands of a clock....
if "H" is the hours and "M" is the mins...then angle can be directly obtained by
ANGLE = 30H - (11/2)M
For example...when da time is 9:30...angle is
30*9 - (11/2)*30 = 270-165=105 degrees..

hope dat was useful.....

The above formula ANGLE = 30H - (11/2) M is obtained as follows :

For hour hand :
12*60 = 360
=> x min = x/2

For min hand :
60 min = 360 => x min = 6x

total min = h*60+m

so diff = (h*60+m)/2 - 6m = 30h - (11/2)m

Let time be given as H:M where H is Hours and M is Minutes.
Angle covered by Hour hand in covering H hours = (H%12)*30 degrees
Additional angle covered by Hour hand in covering M minutes = (M%60)/2 degrees

Angle covered by Minute hand= (M%60)*6 degrees
So difference between them
abs( (H%12)*30 + (M%60)/2 - (M%60)*6 )
==> abs( (H%12)*30 - ((M%60)*11)/2 ) degrees

static double angleBetweenHourAndMinuteHand(double hour,double minute){
		
		double thour = (hour *30) + (30 * ((minute * 6)/360));
		double angle = Math.abs((thour) - (minute * 6));
		return angle > 180 ? 360 - angle : angle;
	}

30 * HH - 5.5 * MM

static double