Interview Question


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select stat1.age,stat1.standing
from (select s.age as age,s.standing as standing, count(*) as c
from student s
group by s.age,s.standing) as stat1
group by stat1.age,stat1.standing,stat1.c
having stat1.c>ALL(select count(*)
from student s2
where stat1.age=s2.age and stat1.standing<>s2.standing
group by s2.age,s2.standing);

- Saron July 18, 2013 | Flag Reply


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