CareerCup

Use a map, initialize it to 0.
Then iterate over the array incrementing the value of map.
Now re-iterate and if the value of any map is greater than 1 then duplicates exist. So print the number out.

@Vinodh: You can store in hash map, both the no. (as key) and the count (as value). Print both key and value using getKey() and getValue().

array= [30, 20, 20, 20,30, 68, 23]
count=1
total=0
dict={}
for x in range (0, len(array)):
    if dict.has_key(array[x]):
        dict[array[x]] = dict[array[x]] + 1
    else:
        dict[array[x]] = 1

for item in dict:
    if dict[item] != 1:
        print item, dict[item]