Interview Question


Country: India




Comment hidden because of low score. Click to expand.
1
of 1 vote

It can be done in many ways either use standard libraries like NTL google it or by designing own class or method. get the value into two string say num1 & num2
num1=123456789123456789123456789
num2=111111111111111111111111111
first make 2 string of same length by adding leading zeros.
now do the addition as we do by using copy pen.
int j=0;
for(i=strlen(num1);i>=0;i--)
{
num3[j]=num1[i]+num2[i]+carry;
carry=num3[j]/10;
num3[j]%=10;
j++;
}
if(carry)
num[j]=carry;

and print num3 in reverse order

- dabbcomputers March 20, 2012 | Flag Reply
Comment hidden because of low score. Click to expand.
1
of 1 vote

You can try it with Link list

- rahul chaudhary March 20, 2012 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 votes

double liked list with additional pointers root and tail

- tsarapin March 20, 2012 | Flag


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