Microsoft Interview Question






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0
of 0 vote

//1'st node
if (list == toDelete)
{
list = toDelete->next
delete (toDelete)
return
}
prev = list
while(prev->next != toDelete) prev = prev->next
// in case of last element
if toDelete->next == NULL
prev->next = NULL
else
prev->next = toDelete->next

delete(toDelete)

test:
empty list
1 element list - delete element
2 element list - 1st to delete, 2nd to delete
3 element list - 1st to delete, 2nd to delete, last to delete
4 element list - 1st to delete, 2nd to delete, last to delete
10 element - 1st to delete, 6nd to delete, last to delete
100 element - 1st to delete, 6nd to delete, last to delete, delete the whole list

performance with long list

- Eila June 11, 2006 | Flag Reply


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