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it will print %%

To print % with printf , format specifier %% should be used .

so the above asked question returns error for prrintf(), it should be printf

if you fix it , the answer would be %%.

prints random numbers.. and while compilation it gives warnings about format string..

prints random numbers

It prints some garbage values, i guess.

it will print %%

Out put will be %%%%

it will print %% coz % specifier is used to print % symbol

i think you mistyped prrintf instead of printf

its output is %%

The output is %%.

%%.
if you want to print % in STDOUT then use %% in printf

Stupid interview question.

o/p %%

error in 5th line

it prints
%%

it will print %%

#include<stdio.h>
#include<conio.h>
main()
{
printf("%\%");
getch();
}

spelling of printf is prrintf so it will throw a typo error

koi naukri lagwado yaaaar