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what do u meant by short circuiting ??? what abt prcedence of operators??

But tell me if unary operators have the highest precedence among all (actually second highest)....then why here we are bothering about "&&" or "||"......first unary operators should be evaluated.... according to ur explanation answer is right but how ??? why we are not evaluating unary operators first ????
second thing in denis and ritchie ANSI C it is given that if their are to expressions f(x) and g(x) in a bigger expression then its not fixed that which of the "f()" or "g()" will be evaluated first.........what exactly it means and if it is so then why we bother about precedence and associativity in evaluating an expression.... clarify it with example

i support mr.deepak since precedence of unary operator is greater than of logical && and logical || operator at first x,y,z values are incremented then or opertion sholud be performed in that way answer should be performed o/p:2,2,1
but why o/p is 2,1,1 when i executed

yes answer is correct but why ??

@deepakyadav1830,
In the expression, Z = ++x||++y&&++z
the answer is coming 2,1,1 due to the OR property, here x is > 0, so according to OR(1 || something) gives the o/p 1 so it never goes to execute "something" .

what "deepakyadav" is telling (i.e regarding f(), g() ) is correct if they are as below:-
x = f() * g();// order of f()/g() evaluation is not defined.
OR
x(f(),g())

BUT in the case of an expression having "||" "&&" and "," the order of evaluation is defined and it is "left->right".