CareerCup

Cant understand question.
by difference you mean angle betn hour hand and minute hand or 'number of mins"?
Or some else?

http://jdw6415.blogspot.com/2009/06/puzzle-difference-between-hour-and.html

double GetAngle(double hh, double deltah, double mm, double deltamm)
{
return (30*(hh+deltah) - 5.5*(mm+deltamm));
}

To find the angle between the hands of a clock....
if "H" is the hours and "M" is the mins...then angle can be directly obtained by
ANGLE = 30H - (11/2)M
For example...when da time is 9:30...angle is
30*9 - (11/2)*30 = 270-165=105 degrees..

[1] Every hour, the hour hand moves 30 degrees
[2] Every minute, the minute hand moves 6 degrees
[3] For every minute, the hour hand moves 0.08 degrees

So, the difference between them in angles is (in C/C++):

diff = abs (((hour * 30) + (0.08 * min)) - (min * 6)))

[1] Hour hand rotates 30 degree per hour thus .5 degree per minute.
[2] Minute hand rotates 6 degree per minute
so for a time HH:MM:00
Angle of Minute hand MAngle = MM * 6
Angle of Hour Hand HAngle = HH * 30 + MM * .5
Angle between the two is : abs (MAngle - HAngle)
Thanks,
Appy

Girish Nandagudi's answer is fine with the replacement of .08 by .5 as mentioned by Anonymous.

(360/12)*(hrs%12) + (360/12)*(minutes/60) - 360*(minutes/60)

Try This:-

find find angles made by each hand with respect to 12.00p.m
AngleMinute = m*6
AngleHour = h*30 + 0.5*m

return AngleMinute - AngleHour