Interview Question
Country: India
The question has some issue. If 0.25 is the answer to the question, uniformly picking among a) to d) would have a chance of 0.5 guessing it to be 0.25(picking a) or c)). But 0.5 is not the answer to the question!
If 0.5 is the answer, uniformly picking among a) to d) would have a chance of 0.25 guessing it 0.5 (picking d)), but 0.25 is not the answer to the question either!
So, my conclusion is that the question intrinsically has contradiction such that there is no answer.
The probability of getting any option is 1/4.
Then the probability of an option to be correct is 1/2.
So the probability of an randomly chosen answer to be correct is 1/4 X 1/2 = 1/8
So for all the four option if we take the sum of probabities then it should be :
1/8 X 4 = 1/2 = 0.50
I think we need to calculate the probability, rather than choosing from the given options. The options look like part of the question and we are not required (and should not) choose the given values.
My answer:
Since there are three unique answers, each has 1/3 chance of being correct. Also (0.25) appears twice, so it has 1/2 probability of being chosen; the rest have 1/4 probability of being chosen. So,
P(0.25 is right answer and it is chosen) = P(0.25 is correct) x P(0.25 is chosen) = 1/3 x 1/2 = 1/6
P(0.6 is correct and it is chosen) = 1/3 x 1/4 = 1/12
P(0.5 is correct and it is chosen) = 1/12
P(choosing randomly and it being correct) = 1/4 x 1/3 = 1/12
we r choosing ans randomly then d probability wud be 1/4...(don.'t care about d options)
Well, it actually depends on how you want to view the question. If you regard as the numbers being the options, then yes D is the correct answer.
But let's say that the answer randomly chosen is the actual letter in the set {A, B, C, D} and we do not care about the number. Then, actually, the answer would be 25%.
Ans can be right or wrong,probability for getting it right is always 1/2 means 0.50.
So that 'd' is correct option.
d
- Vincent August 25, 2012