CareerCup

inverse transformation: 2*sqrt(rand())

Why sqrt?

better way is lets have array and repeat number equivalent to the probability you want say for this case array will consists of 0,1,1,2,2,2,2 now we can use this rand function in this way

#define ArrayMax 6 // our index starts from 0
for (int i=0;i<ArrayMax;i++)
{
print ("\t Arr[i*rand()]");
}


this is some sort of the way we can do it

comments are welcome

CUNOMAD's solution looks cool to me!

The solution " 2*sqrt(rand()) " needs some explanation.

I am the original poster. I forgot to mention that the numbers are not necessarily integers. In other words, the numbers generated by rand() can be any real number between 0 and 1. It is not the same as the C++ rand() function.

ONLY change in my previous code will be have float array instead of integer

I would consider just multiplying the random number by 2.