Bank of America Interview Question for Java Developers


Country: United States




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1
of 1 vote

You can sort the map on the basis of timestamp, and then remove the elements after t1.
It can be achieved if map is tree map implementation, and comparator sorts the map on the baisis of value and that also on parameter timestamp.

- OTR April 11, 2013 | Flag Reply
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0
of 0 votes

Time complexity to remove n session objects out of total N session objects will be O(log(N)+n)

- Karthik April 12, 2013 | Flag
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1
of 1 vote

Create a map<timestamp,sessionid>, find key=t1 and remove all sessions from original map with sessionid having timestamp > t1.

- kanhaiya.baranwal April 07, 2015 | Flag Reply
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0
of 0 vote

In practice, these sessionObjects are mostly stored in Memcached and set a TTL equal to session timeout in the site. Memcached doesn't proactively remove the object after TTL has passed but removed them when it is read or during GC.

- Karthik April 12, 2013 | Flag Reply
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0
of 0 vote

Make a treemap and use tailmap on t1

- Neha Chhatwani June 29, 2016 | Flag Reply
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0
of 0 vote

Make a treemap and apply tailmap on t1

- Neha Chhatwani June 29, 2016 | Flag Reply


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