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it should be segfault since when we do int *p=1 it means we are assigning non lvalue to a pointer variable

Ans 5

p is pointing to address 1
p++ is p +=4
now p is pointing to address 5

@ Gaurav: how do you know that 1 is an address. read the question properly. its a value and cunomad is right, as we're trying to put some value to some undefined memory location hence it will lead to a "Seg Fault".

Here the definition and assignment of 'p' is being done in single statement.
int *p=1 -> int *p, p=1; and not int *p, *p=1.

Also in printf we are printing 'p' and not '*p'.
If we print '*p' we get a seg fault.

Gaurav gives a good answer, even we know it is an illegal address, it'll be no hurt to print out the address as an integer, though accessing the value of such address will generate a segment fault.

printing p will not lead to seg-fault but *p will, so gaurav's answer is right @googler

Compilation error at line 1

error C2440: 'initializing' : cannot convert from 'int' to 'int *'

depends on compiler.....c should make it pass though i guess

The answer indeed is 5, with a DevC++ compiler for a C file.
But if you are right, p is pointing to address 1. If I change the next line as p--, it gives me -3 as the answer. How can it point to address -3?

guys its pretty clear that p is an integer pointer and incrementing that makes it point to the next integer and its perfectly legal to print the address of the pointer [printing the value pointed to may give segmentation fault errors]. Here is the output of compiling/running using gcc4.3 on linux:

kk@kk-laptop:~$ gcc temp.c 
temp.c: In function ‘main’:
temp.c:5: warning: initialization makes pointer from integer without a cast
temp.c:7: warning: format ‘%d’ expects type ‘int’, but argument 2 has type ‘int *’
temp.c:4: warning: return type of ‘main’ is not ‘int’
kk@kk-laptop:~$ ./a.out 
5

If we use the C compiler, it will just give warning of invalid cast.
But C++ is more strict compiler in terms of casting and it will give error on int *p = 1 saying u can convert int to int*

-Peace :-)

I mean u cannot convert .. a little typo :-)