CareerCup

void hex(int num){
int rem;
if(!num)
return;
hex(num/16) ;
rem=num%16;
printf("%c",(rem<10)? '0'+rem :('A'+rem-10));
return;
}

printhex(int a){
if (a <10 )
printf(%d,a);
else
if (a <16)
printf (%c, 55+a);
else
 
}

@neo
incomplete code...

@CUNOMAD
what exactly you mean by saying "implements %x in printf without using printf"... not clear enough.

@googler u cant use standard %x for printing

@cunomad
then the question shud be: print the hex value without using the default %x available in printf for the same...anyways you've to use printf finally, right?

we cant use printf

lol
the first solution uses printf. if printf is not allowed then what is the answer?

#include<stdio.h>
#include <unistd.h>
#include <stdlib.h>

char getHex(int num)
{
     if (num < 10 )
        return (char)(num+48);
     if (num < 16 )
        return (char)(num+55);
}

int printhex(int x)
{
    // Convert the input to HEX
    char tmpresult[100];
    char result[100];
    int remainder=0, indx=0, i = 0, j = 0;
    while(x)
    {
       remainder = x%16;
       x = x/16;
       tmpresult[indx++] = getHex(remainder);
    }

    for ( int i=0, j=indx-1; i < indx ; i++, j--)
       result[j] = tmpresult[i];
    // write to output
    write(1, result, indx);
    return 0;
}

int main(int argc, char* argv[])
{
   printhex(atoi(argv[1]));
   return 0;
}

#include<stdio.h>
#include <stdlib.h>

char getHex(int num)
{
     if (num < 10 )
        return (char)(num+48);
     if (num < 16 )
        return (char)(num+55);
}

int printhex(int x)
{
    if ((x/16 == 0) && (x < 16))
    {
        putchar(getHex(x%16));
        return 0;
    }
    printhex(x/16);
    putchar(getHex(x%16));
}


int main(int argc, char* argv[])
{
   printhex(atoi(argv[1]));
   return 0;
}

string itoh(int i)
{
stringstream ss;
ss<<hex<<i;
std::string retval;
retval=ss.str().c_str();
return retval;
}

#include<stdio.h>
int hex(int num);
void main()
{
int num;
printf("Enter value for num \n");
scanf("%d",&num);
printf("Hexadecimal number is : ");
hex(num);
printf("\b\n\n");
}

int hex(int num)
{
if(num<16)
{
if((num)<10)
printf("%d",num);
else
printf("%c",'A'+num-10);
return 0;
}
else
{
if((num/16)<10)
printf("%d",num/16);
else
printf("%c",'A'+(num/16)-10);
hex(num%16);
}
}

void printhex(int a)

{

for (int i = 0; i < 32; i += 4) {

int c = (a >> i) & 0xF;

if (c <= 9)

putchar(‘0’ + c);

else

putchar(‘a’ + c - 10);

}
}