CareerCup

I think we can solve this problem using two logs...


_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _D _ _ _ _L _ _ _ _ ( C )
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| L | |
| | |L
| _ _ _ _ _ _ _ _ _ _ _ _ _ _ |______________ |
| | ( A ) | L | ( B )
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| |_ _ _ _ _ _ _ _ _ _ _ _ _ _| |
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As we can see the distance between the squares is L. So it gives us the another square ABCD with sides length L.

now parallel to diagonal BD put a log at a distance slightly less than L/2 from C vertex. after that put another log along AC diagonal .
So that it makes " T " structure.

This solution is not mine but mayank on cc chat. He says that the wooden blocks L can be tilted so that we could use their hypotenuse which is definetely larger than L. It does not matter if the block is a rectangle or square shaped the diagonals is larger and we use them to cross the water.

Great, patron!

and     a,   b,,,,c

_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _D _ _ _ _L _ _ _ _ ( C )
| | |
| L | |
| | |L
| _ _ _ _ _ _ _ _ _ _ _ _ _ _ |______________ |
| | ( A ) | L | ( B )
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| | | |
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| |_ _ _ _ _ _ _ _ _ _ _ _ _ _| |
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|_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _|

wow!!! Patron..soln was amazing

Cant we use the concept that wood floats.

@ Patron not sure it would work...

L/squareroot(2) + L/(2*squareroot(2)) < L doesn't hold TRUE

nahi samajh aaya kucch.... patron bhaiya, fir se samjha do ek baar...

{. hi . . }
{ . . }

As given in the problem,the length of the wooden block is L.Therefore,it should also have a width,let us say,"w"(coz it is a wooden block and therefore,is rectangular in shape).
Hence,the diagonal of the wooden block should be definitely greater than L.Hence,the wooden block should be tilted in a manner so that the tips of the diagonal are touching the land of each square.That is what mentioned by prolific.coder

place a block on one corner of bigger block and now placed other block whose one end is on the center of this block and later on the smaller square