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It's harder to understand the question than to actually find the solution.

no answers

6210001000
----------
0123456789

answer is 6 2 1 0 0 0 1 0 0 0
here we find 6 zeros , 1 six , 2 ones and 1 two
so the sum is 6+2+1+1=10

the sum of those digits in the number has to be 10
A+B+...+K=10
since they are the number of respective (based on pocession) digits in that number .

whenever asking a question please give complete examples or clearly explains the problem

7100000100
----------
0123456789

8100000000
----------
0123456789

9 000 000 000

Anur and Chandra ..
Cant u see that 8 and 9 is also appearing.. So the number corresponding 2 I and J should be 1.. That would mess up everything..

x+2y=10
x is the number of zeros
y is the number of ones.
in this case , x should always be even number.
so try with 2,4,6,8

Hey Guys ..

I was not able to understand any of the solutions ..
Can anybody please elaborate more on the solutions, or provide steps in detail

Yes Aj,I too agree.I was not able to follow any of the solutions,someone kindly post the entire question and what is expected.Honestly from the question i was not able to figfure out why these answers where posted.

if six 0's,2 ones,1 two & 1 six =10 then even 7 0's ,2 one's and 1 two can make it 7+2+1=10

7100000100
0123456789

Another variant of this question:
Find the no. of
0's---
1's---
2's---
3's---
4's---
...
9's---
in this question.

Take any 10 digit number and start moving.
eg.-

lets take -
0123400000 // sum of digits is 10

4123410000 ->
4213410000 ->
5210401000 ->
6210001000

0123456789
6210001000

Number is : 6210001000
public class puzzle
{

static int a[]=new int[10];

static int getNumberCount(int searchnumber)
{
int count=0;
for(int i=0;i<10;i++)
{
if(a[i]==searchnumber)
count++;
}
return count;
}

public static void main(String args[])
{
for(a[0]=1;a[0]<=9;a[0]++)
for(a[1]=0;a[1]<=9;a[1]++)
for(a[2]=0;a[2]<=9;a[2]++)
for(a[3]=0;a[3]<=9;a[3]++)
for(a[4]=0;a[4]<=9;a[4]++)
for(a[5]=0;a[5]<=9;a[5]++)
for(a[6]=0;a[6]<=9;a[6]++)
for(a[7]=0;a[7]<=9;a[7]++)
for(a[8]=0;a[8]<=9;a[8]++)
for(a[9]=0;a[9]<=9;a[9]++)
{
if(a[0]==getNumberCount(0) && a[1]==getNumberCount(1) &&a[2]==getNumberCount(2) &&a[3]==getNumberCount(3) &&a[4]==getNumberCount(4) &&a[5]==getNumberCount(5)&&a[6]==getNumberCount(6)&&a[7]==getNumberCount(7)&&a[8]==getNumberCount(8)&&a[9]==getNumberCount(9))
System.out.println("Number : "+a[0]+a[1]+a[2]+a[3]+a[4]+a[5]+a[6]+a[7]+a[8]+a[9]);
}
}
}

Number is : 6210001000

public class puzzle
{

static int a[]=new int[10];

static int getNumberCount(int searchnumber)
{
int count=0;
for(int i=0;i<10;i++)
{
if(a[i]==searchnumber)
count++;
}
return count;
}

public static void main(String args[])
{
for(a[0]=1;a[0]<=9;a[0]++)
for(a[1]=0;a[1]<=9;a[1]++)
for(a[2]=0;a[2]<=9;a[2]++)
for(a[3]=0;a[3]<=9;a[3]++)
for(a[4]=0;a[4]<=9;a[4]++)
for(a[5]=0;a[5]<=9;a[5]++)
for(a[6]=0;a[6]<=9;a[6]++)
for(a[7]=0;a[7]<=9;a[7]++)
for(a[8]=0;a[8]<=9;a[8]++)
for(a[9]=0;a[9]<=9;a[9]++)
{
if(a[0]==getNumberCount(0) && a[1]==getNumberCount(1) &&a[2]==getNumberCount(2) &&a[3]==getNumberCount(3) &&a[4]==getNumberCount(4) &&a[5]==getNumberCount(5)&&a[6]==getNumberCount(6)&&a[7]==getNumberCount(7)&&a[8]==getNumberCount(8)&&a[9]==getNumberCount(9))
System.out.println("Number : "+a[0]+a[1]+a[2]+a[3]+a[4]+a[5]+a[6]+a[7]+a[8]+a[9]);
}
}
}

This question provides the answer in the question itsel, then what on earth are we to find?

This question provides the answer in the question itsel, then what on earth are we to find?

This question provides the answer in the question itsel, then what on earth are we to find?

for 8 igit number its:

42101000

(asked in amazon)

4-digit number is:
1210
5-digit number is:
21200
7-digit number is:
3211000

You gus are retarded

The answer is