MIH Interview Question for Software Engineer / Developers






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let n1,n2 be length of 1st and 2nd lists resp. Start traversing longer list at abs(n1-n2). Now just compare the addresses.

- vineet May 23, 2007 | Flag Reply
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vineet :
How is that possible if the list members are allocated dynamically ?

Can the question poster elaborate on the question ?

- knap October 14, 2008 | Flag Reply


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