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Bloomberg LP Interview Question for Financial Software Developers


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of 0 vote

Here i forgot the part mentioned in the main , but i think it was some thing like String s = "asas";

- TopCoder February 23, 2010 | Flag Reply
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0
of 0 vote

It will compile... it will even run if you put the declaration:
String s = "asas"
in the main program. However, since the constructors and assignment operator are empty and there is no storage associated with the class, no data will ever be associated with the class which makes it of very questionable usefulness.

- Anonymous February 28, 2010 | Flag Reply
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of 0 votes

Its tricky. The constructor is declared as explicit. So declarations of the form String s ="asas"; may be illegal.
However the explicit constructor's parameter list has only a char ch and not a character array, which the non-explicit constructor has (char *p), so in this case String s ="asas" should compile.

- p March 01, 2010 | Flag
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of 0 votes

If the 2 constructor was not declared to be explicit then the code will not compile. The reason for that is the call to the constructor will be ambiguous.
Now when the 2 constructor is declared explicit the ambiguity is removed when we declare objects of the type string s1= "abc".
Ambiguity still exists when object is created this way
string s1("abc")
google "c++ explicit" for the reason, I am unable to post link to the web page

- abhimanipal May 06, 2010 | Flag
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of 0 vote

However the assignment operator is private. Iam not sure whether calling String s="asa" in main() would compile.

- Musheka March 27, 2010 | Flag Reply
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of 0 vote

My apologies for the previous answer. For a moment I forgot that "copy constructor" is called when you create a string like string s = "asas"

- Musheka March 27, 2010 | Flag Reply
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0
of 0 vote

try these

String s = "ddas"; // OK it calls "String(const char *p){} "

String s1 = 'd'; // error should explicitly call the ctor

String s2 ('d'); // OK

- Mostafa April 26, 2016 | Flag Reply
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0
of 0 vote

Yes

- Anonymous May 25, 2021 | Flag Reply


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