Two Sigma Interview Question for Software Engineer / Developers






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i didn't understand the problem can u please explain this problem in detail.

- gaurav October 26, 2010 | Flag Reply
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1. put the string in hashtable.
2. Compare the pangram starting from A till Z.
3. If the character is found in hashtable, move to next character. If not found, maintain another string of missing letters and put the missing character in this string.

- Richa Aggarwal October 27, 2010 | Flag Reply
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Can u explain the question a little bit clear???pls..

- Hellan December 28, 2010 | Flag Reply
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Check wiki for 'Pangram'

Pangram string is missing some alphabets. Find them..

- curiousTiger May 26, 2012 | Flag Reply
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public String missingPangrams(String inputStr){
        StringBuilder str = new StringBuilder();
        char offset = 'a';
        BitSet b = new BitSet(26);
        b.set(0,25,false);
        if(inputStr != null && inputStr.isEmpty()) {
            inputStr = inputStr.toLowerCase();
            for (int i = 0; i < inputStr.length(); i++) {
                b.set(inputStr.charAt(i) - offset, true);
            }
        }

        for (int i = 0; i < 26; i++) {
            if(!b.get(i)) str.append((char)(offset + i));
        }
        return str.toString();

}

- devnullfin June 08, 2017 | Flag Reply
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public String missingPangrams(String inputStr){
        StringBuilder str = new StringBuilder();
        char offset = 'a';
        BitSet b = new BitSet(26);
        b.set(0,25,false);
        if(inputStr != null && inputStr.isEmpty()) {
            inputStr = inputStr.toLowerCase();
            for (int i = 0; i < inputStr.length(); i++) {
                b.set(inputStr.charAt(i) - offset, true);
            }
        }

        for (int i = 0; i < 26; i++) {
            if(!b.get(i)) str.append((char)(offset + i));
        }
        return str.toString();

}

- devnullfin June 08, 2017 | Flag Reply
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of 0 vote

public String missingPangrams(String inputStr){
StringBuilder str = new StringBuilder();
char offset = 'a';
BitSet b = new BitSet(26);
b.set(0,25,false);
if(inputStr != null && inputStr.isEmpty()) {
inputStr = inputStr.toLowerCase();
for (int i = 0; i < inputStr.length(); i++) {
b.set(inputStr.charAt(i) - offset, true);
}
}

for (int i = 0; i < 26; i++) {
if(!b.get(i)) str.append((char)(offset + i));
}
return str.toString();
}

- devnullfin June 08, 2017 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

public String missingPangrams(String inputStr){
        StringBuilder str = new StringBuilder();
        char offset = 'a';
        BitSet b = new BitSet(26);
        b.set(0,25,false);
        if(inputStr != null && inputStr.isEmpty()) {
            inputStr = inputStr.toLowerCase();
            for (int i = 0; i < inputStr.length(); i++) {
                b.set(inputStr.charAt(i) - offset, true);
            }
        }

        for (int i = 0; i < 26; i++) {
            if(!b.get(i)) str.append((char)(offset + i));
        }
        return str.toString();
    }

- devnullfin June 08, 2017 | Flag Reply


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