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Bloomberg LP Interview Question for Software Engineer / Developers


More Questions from This Interview



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1
of 1 vote

kunths shuffle

- Anonymous November 09, 2010 | Flag Reply
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0
of 0 votes

Yep. this works

- Synonymous November 21, 2010 | Flag
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0
of 0 vote

Will this work?
(rand()%n)*n/m

- Kannan October 22, 2010 | Flag Reply
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0
of 0 votes

the question is that we should develop our own rand() function

- roshan January 16, 2014 | Flag
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0
of 0 vote

(rand()%n)*m/n

- Anonymous October 22, 2010 | Flag Reply
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0
of 0 vote

(1+rand()%n)*m/n

- Anonymous October 22, 2010 | Flag Reply
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0
of 0 vote

Given an array of 1 to n.
Choose random number between indices 0 and n-1. Return that element. Replace element with rightmost element in array.
Now choose random number between indices 0 and n-2.
Repeat above m times.

- Metta October 25, 2010 | Flag Reply
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0
of 0 votes

@metta I am not sure of this but i think your algorithm may not work, since you are restricting each element to be selected only once. In a randomly selected m elements, there is a probability for element to repeat. But in your algorithm, elements do not repeat at all.

- Anonymour November 17, 2010 | Flag
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0
of 0 votes

oh shit I am sorry. I read the question wrongly.. Ya your algo will work perfectly then. :)

- Anonymour November 17, 2010 | Flag


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