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Not sure what exactly is the expected pattern. It looks like you need 4 bits from bit 2 to bit 5. Can this work

#define unknown_bit_process(x)         ((x) >> 2) & 0xf)

LOL @ Sreekanth

Are you a moron?

package test;

public class binary
{

public static void main(String arg[])
{
String s = "11000011";
for(int i=0; i<s.length() ; i++)
{
if(i+1 < s.length() && s.charAt(i)!= s.charAt(i+1))
{
int index = i+1;
char c = s.charAt(index);
System.out.print(c);

for(int j = i+2 ; j < s.length(); j++)
{
if(j+1 < s.length() && c != s.charAt(j))
{
break;
}
else
{
System.out.print(s.charAt(j));
}
}

break;


}

}
}

}

package test;

public class binary
{

public static void main(String arg[])
{
String s = "11000011";
for(int i=0; i<s.length() ; i++)
{
if(i+1 < s.length() && s.charAt(i)!= s.charAt(i+1))
{
int index = i+1;
char c = s.charAt(index);
System.out.print(c);

for(int j = i+2 ; j < s.length(); j++)
{
if(j+1 < s.length() && c != s.charAt(j))
{
break;
}
else
{
System.out.print(s.charAt(j));
}
}

break;


}

}
}

}

package test;

public class binary 
{

	public static void main(String arg[])
	{
		String s = "11000011";
		for(int i=0; i<s.length() ; i++)
		{
			if(i+1 < s.length() && s.charAt(i)!= s.charAt(i+1))
			{
				int index = i+1;
				char c = s.charAt(index);
				System.out.print(c);
				
				for(int j = i+2 ; j < s.length(); j++)
				{
					if(j+1 < s.length() && c != s.charAt(j))
					{
						break;
					}
					else
					{
						System.out.print(s.charAt(j));
					}
				}
				
				break;	
					
					
				}
				
			}
		}
	
}

Hi can any one help me.....i have one question for......

Print how many arguments passed in function...using c language..
mail id: battu.jeevan1991@gmail.com