Philips Interview Question for Backend Developers


Country: India




Comment hidden because of low score. Click to expand.
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of 0 vote

public static void main(String[] args) {
int sum=121;

int firstNum=0;
int secondNum=0;

int thridNum=sum/11;

List<Integer> firstList=new ArrayList<Integer>();
List<Integer> secondList=new ArrayList<Integer>();

for (int i=1;i<=9;i++){
for (int j=1;j<=9;j++){
int addtion4thirdnum=i+j;
if(addtion4thirdnum==thridNum){
firstList.add(i);
secondList.add(j);
}
}
}

for (int i=0;i<firstList.size();i++){
int tempFirstNum=Integer.parseInt(String.valueOf(firstList.get(i)).concat(String.valueOf(secondList.get(i))));
int tempSecondNum=Integer.parseInt(String.valueOf(secondList.get(i)).concat(String.valueOf(firstList.get(i))));

if( (tempFirstNum+tempSecondNum) == sum){
firstNum=tempFirstNum;
secondNum=tempSecondNum;
}
}

System.out.println("firstNum: "+firstNum);
System.out.println("secondNum: "+secondNum);
}

- Anonymous September 11, 2018 | Flag Reply
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0
of 0 vote

package test;

import java.util.ArrayList;
import java.util.List;

public class GaneshTest2 {

public static void main(String[] args) {
int sum=121;

int firstNum=0;
int secondNum=0;

int thridNum=sum/11;

List<Integer> firstList=new ArrayList<Integer>();
List<Integer> secondList=new ArrayList<Integer>();

for (int i=1;i<=9;i++){
for (int j=1;j<=9;j++){
int addtion4thirdnum=i+j;
if(addtion4thirdnum==thridNum){
firstList.add(i);
secondList.add(j);
}
}
}

for (int i=0;i<firstList.size();i++){
int tempFirstNum=Integer.parseInt(String.valueOf(firstList.get(i)).concat(String.valueOf(secondList.get(i))));
int tempSecondNum=Integer.parseInt(String.valueOf(secondList.get(i)).concat(String.valueOf(firstList.get(i))));
if( (tempFirstNum+tempSecondNum) == sum){
firstNum=tempFirstNum;
secondNum=tempSecondNum;
}
}

System.out.println("firstNum: "+firstNum);
System.out.println("secondNum: "+secondNum);
}

}

- Sambit Mishra September 11, 2018 | Flag Reply
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0
of 0 vote

import java.util.Scanner;
public class Solution 
{

	public static void main(String[] args)
	{
		Scanner in = new Scanner(System.in);
		
		String str = in.nextLine();
		String[] inp = str.split(",");
		
		System.out.println(isSpecial(inp,inp.length));
	}
	
	public static int isSpecial(String[] inp, int inpSize) 
	{
		int arr[] = new int[inp.length];
		for(int i=0;i<inpSize;i++) 
		{
			arr[i] = Integer.parseInt(inp[i]);
		}
		
		int spclCount = 0;
		for(int i=0;i<arr.length;i++) 
		{
			for(int j=1;j<((arr[i]/2)+1);j++) 
			{
				if(j+getReverse(j) == arr[i]) 
				{
					spclCount++;
					break;
				}
			}
		}
		
		return spclCount;
	}
	
	public static int getReverse(int n) 
	{
		int rem,rev=0;
		while(n != 0)
		{
			rem = n % 10;
			rev = (rev*10) + rem;
			n /= 10;
		}
		return rev;
	}

}

- Here is a brute-force approach in JAVA and this can be optimised, March 24, 2021 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

import java.util.Scanner;
public class Solution
{

public static void main(String[] args)
{
Scanner in = new Scanner(System.in);

String str = in.nextLine();
String[] inp = str.split(",");

System.out.println(isSpecial(inp,inp.length));
}

public static int isSpecial(String[] inp, int inpSize)
{
int arr[] = new int[inp.length];
for(int i=0;i<inpSize;i++)
{
arr[i] = Integer.parseInt(inp[i]);
}

int spclCount = 0;
for(int i=0;i<arr.length;i++)
{
for(int j=1;j<((arr[i]/2)+1);j++)
{
if(j+getReverse(j) == arr[i])
{
spclCount++;
break;
}
}
}

return spclCount;
}

public static int getReverse(int n)
{
int rem,rev=0;
while(n != 0)
{
rem = n % 10;
rev = (rev*10) + rem;
n /= 10;
}
return rev;
}

}

- Here is a brute-force approach in JAVA and this can be optimised, March 24, 2021 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

Here is a brute-force approach and this can be optimised,

import java.util.Scanner;
public class Solution 
{

	public static void main(String[] args)
	{
		Scanner in = new Scanner(System.in);
		
		String str = in.nextLine();
		String[] inp = str.split(",");
		
		System.out.println(isSpecial(inp,inp.length));
	}
	
	public static int isSpecial(String[] inp, int inpSize) 
	{
		int arr[] = new int[inp.length];
		for(int i=0;i<inpSize;i++) 
		{
			arr[i] = Integer.parseInt(inp[i]);
		}
		
		int spclCount = 0;
		for(int i=0;i<arr.length;i++) 
		{
			for(int j=1;j<((arr[i]/2)+1);j++) 
			{
				if(j+getReverse(j) == arr[i]) 
				{
					spclCount++;
					break;
				}
			}
		}
		
		return spclCount;
	}
	
	public static int getReverse(int n) 
	{
		int rem,rev=0;
		while(n != 0)
		{
			rem = n % 10;
			rev = (rev*10) + rem;
			n /= 10;
		}
		return rev;
	}

}

- Chandra Varshith March 24, 2021 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

321
123

- Anonymous November 13, 2021 | Flag Reply


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