NetApp Interview Question for Analysts

Team: Bigdata analyst
Country: India
Interview Type: In-Person

Comment hidden because of low score. Click to expand.
of 2 vote

The question does not make sense if the point is to have "abc" and "ABC" mapped to different hash values. It already does that by default.

If the point was to consider "abc" and "ABC" as the same key, we would have to override the hashCode() and equal() of the type we're putting in the HashMap.
This would make more sense as an interview question.

- Miguel Oliveira August 31, 2013 | Flag Reply
Comment hidden because of low score. Click to expand.
of 0 vote

HashMap's put() and get() methods utilize the hashCode() and equals() function. Note that 'abc' and 'ABC' are distinct separate values. As such, the hashCode(abc) and hashCode(ABC) will result in different key values.

On the other side, let's say that we have a key collision and we're trying to retrieve a case sensitive value from the resulting LinkList that is created at that bucket entry. Then the .equals(abc) and .equals(ABC) can clearly distinguish what value you are seeking.

- masterjaso August 31, 2013 | Flag Reply
Comment hidden because of low score. Click to expand.
of 0 vote

consider the string str[]="abAcD"

and if this should be hashed to the string str[]="abacd"

then toupper(str[i])-'a' would give the same result for both of them .

- ram rs September 10, 2013 | Flag Reply

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