CareerCup

7|1|6|4
-------
5|3|8|2

I'll try a heuristic,
the middle boxes are surrounded with more number boxes, our goal is to not to have neighbors. so lets take a number from 1 to 8 that has less neighbors which is either 1 or 8.
place it in the middle 4 boxes then alternatively place continuous elements

- 1 - -        - 1 - 2            - 1 - 2          - 1 - 2
- - - -        - - - -            - 3 - -          - 3 - 4

and then

5 1 - 2        5 1 6 2            5 1 6 2          5 1 6 2        
- 3 - 4        - 3 - 4            7 3 - 4          7 3 8 4

you could try selecting different box for 1 as below:

- - - -        - - - -            - - 3 -          4 - 3 -
- - 1 -        2 - 1 -            2 - 1 -          2 - 1 -

and then

4 - 3 -        4 - 3 -            4 - 3 7          4 8 3 7 
2 - 1 5        2 6 1 5            2 6 1 5          2 6 1 5

feel free to suggest advanced heuristics. thanks

Let me try to formalize it
1. Divide even and odd in halfs
Since any pair of consecutive number consists of an even and an odd
number hence these two cannot be in the same half.
2 Place 1 and 8 on the separation line between even and odd.
Since 1 and 8 have affinity for one number only hence solution is
possible.
Comments and inputs are welcome

Another way could be: 1-5-4-8
in second line: 3-7-2-6

Arrange odd number on left four block and even number on right four block and vice versa. And try to do some manupulation.
e.g
7 5 8 2
3 1 6 4

7 3 8 2
5 1 6 4

Can it be also this:
1 5 2 6
3 7 4 8

How abt this?
1625
3847

It can be
1 5 8 4
7 3 2 6