CareerCup

tuesday + ((64-11)*365 + 52/4 (leap year days) + 31 + 28 + 6) % 7

void main()
{
   printf("sunday");
}

It was the question in math test or programming test?

import datetime

day = ['Sunday', 'Monday', 'Tuesday', 'Wednesday','Thursday','Friday','Saturday' ]
t1 = datetime.date(2011,1,1)
t2 = datetime.date(2064,3,6)

delta_t = (2+(abs((t2-t1).days)))%7
print('If jan 1 2011 is tuesday then March 6 2064 will be {}'.format(day[delta_t]))

day = ['Sunday', 'Monday', 'Tuesday', 'Wednesday','Thursday','Friday','Saturday' ]
t1 = datetime.date(2011,1,1)
t2 = datetime.date(2064,3,6)

delta_t = (2+(abs((t2-t1).days)))%7
print('If jan 1 2011 is tuesday then March 6 2064 will be {}'.format(day[delta_t]))

day = ['Sunday', 'Monday', 'Tuesday', 'Wednesday','Thursday','Friday','Saturday' ]
t1 = datetime.date(2011,1,1)
t2 = datetime.date(2064,3,6)

delta_t = (2+(abs((t2-t1).days)))%7
print('If jan 1 2011 is tuesday then March 6 2064 will be {}'.format(day[delta_t]))

import datetime

mydate = datetime.date(2064,3, 6)  #year, month, day
print(mydate.strftime("%A"))

import datetime

mydate = datetime.date(2064,3, 6)  #year, month, day
print(mydate.strftime("%A"))

String str1= "January 1, 2011";
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("MMMM d, yyyy", Locale.ENGLISH);
LocalDate d1 = LocalDate.parse(str1, formatter);

String str2 = "March 6, 2064";
LocalDate d2 = LocalDate.parse(str2, formatter);

long noOfMiliSecondsInDay = (100 * 60 * 60 * 24)

long totalMiliSec = d1.getTime() - d2.getTime();

long totalDays = totalMiliSec / noOfMiliSecondsInDay ;

int dayDiff = totalDays % 7;