JP Morgan Interview Question for Software Engineers


Country: India




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This question is not clear:
What is the input ?
Give an example and expected result

- steep September 16, 2017 | Flag Reply
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If the input is a single string of numbers (ex '104875'), and the output should be '10*4*87-5', then here is my shot in JavaScript:

function insertStarsDashes(str) {
  let i = 0
  while(i < str.length) {
    const current = str[i]
    const next = str[i + 1]
    // Check if current and next numbers are both even
    if (current % 2 === 0 && next % 2 === 0) {
      // Slice the string into two halves, insert the star
      str = str.slice(0, i+1) + '*' + str.slice(i+1, str.length)
    // If not, check if they are both odd and insert a dash
    } else if (current % 2 === 1 && next % 2 === 1) {
      str = str.slice(0, i+1) + '-' + str.slice(i+1, str.length)
    }
    i++
  }

  return str
}

- cmw228 September 16, 2017 | Flag Reply
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In Java we can write something like below:

public class InsertStarBetweenEvenAndDashBetweenOdd {

	public static void main(String[] args) 
	{
		long l=104875l;
		
		String s= ""+l;
		StringBuilder s2= new StringBuilder("");
		s2.append(s.charAt(0));
		
		for(int i=1;i<s.length();i++)
		{
			int t1= Integer.parseInt(s.charAt(i-1)+"");
			int t2= Integer.parseInt(s.charAt(i)+"");
			s2.append((t1%2==0?(t2%2==0?"*"+s.charAt(i):s.charAt(i)):(t2%2!=0?"-"+s.charAt(i):s.charAt(i)))+"");
			
		}
		System.out.println(s2.toString());

	}

}

- NoName September 21, 2017 | Flag Reply
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(ex '104875'), and the output should be '10*4*87-5'

How do you predict the starting number as 10, instead why cant it be 1 and 0.

- Kiran October 31, 2017 | Flag Reply
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public class InsertcCharBetweenOddAndEven {
	public static void main(String[] args) throws IOException {
	InputStreamReader reader = new InputStreamReader(System.in);
	BufferedReader bfReader = new BufferedReader(reader);
	String line = bfReader.readLine();
	StringBuilder sb = new StringBuilder();
	sb.append(line.charAt(0));
	for(int i=1;i<line.length();i++){
		if(line.charAt(i)%2==0 && line.charAt(i-1)%2==0) {
			sb.append("*"+line.charAt(i));
		}else if(line.charAt(i)%2!=0 && line.charAt(i-1)%2!=0) {
			sb.append("-"+line.charAt(i));
		}
		else {
			sb.append(line.charAt(i));
		}
	}
	System.out.println(sb.toString());
	}
}

- amit December 03, 2017 | Flag Reply
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def insert_bewteen(number):
	strrrr = []
	for i in range(0, len(number) - 1):
		is_last = i == len(number) - 2
		if int(number[i]) % 2 == 0 and int(number[i + 1]) % 2 == 0:
			strrrr.append(number[i] + "*")
		elif int(number[i]) % 2 == 1 and int(number[i + 1]) % 2 == 1:
			strrrr.append(number[i] + "-")
		else:
			strrrr.append(number[i])
		if is_last:
			strrrr.append(number[i + 1]) #gdamn
	print "".join(strrrr)

- ewarrenG January 17, 2018 | Flag Reply


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