Amazon Interview Question for Quality Assurance Engineers


Country: India
Interview Type: In-Person




Comment hidden because of low score. Click to expand.
3
of 3 vote

Just keep a count of the number of zeros and the number of ones, since they can't be intermingled. No data structure even required.

- nilkn January 23, 2014 | Flag Reply
Comment hidden because of low score. Click to expand.
1
of 1 vote

public void addElements(int k) {
		DoubleSidedLnkedList node = new DoubleSidedLnkedList(k);
		if (head == null) {
			head = node;
			temp = node;
		} else if (k == 0) {
			while (temp.previous != null) {
				temp=temp.previous;
			}
			node.next = temp;
			temp.previous=node;
		}
		else{
			while (temp.next != null) {
				temp=temp.next;
			}
			node.previous = temp;
			temp.next=node;
		}
	}

- Anonymous January 23, 2014 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

You can try and solve this using linked list implementation. If input is one you add it at the end of the linked list, if the input is zero you add it at the start. Each time user inputs something, just print the whole linked list.

- SH January 22, 2014 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 votes

Linked List or any other Data Structure cannot be used.

- pal March 03, 2014 | Flag
Comment hidden because of low score. Click to expand.
0
of 0 vote

public Node buildList(int input, Node head) {
	Node temp = new Node();
	Node tempHead = head;
	if (input == null || head == null)
		return null;
		
	if (head.value == null){ // first element
		head.value = input;
		return head; // all done!
	}
	if (input == 1) // add to the end of the list
		while(tempHead.next != null) // iterate to the end of the list
			tempHead = tempHead.next;
		temp.value = input;
		tempHead.next = temp
	else if (input == 0){ // add to beginning
		temp.value = input;
		temp.next = head;
		tempHead = temp; // assign this as the new head
	}

	return tempHead;

}

- uh huh January 23, 2014 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 votes

Undoubtedly not perfect, but basic algorithm

- uh huh January 23, 2014 | Flag
Comment hidden because of low score. Click to expand.
0
of 0 vote

{
{
{#include<stdio.h>
#include<conio.h>
int a[50],b[50],count=0;
void zero(int ,int );
void display();
void zero(int p,int q)
{
int i;
for(i=q;i>=0;i--)
{
b[i+1]=b[i];
}
b[0]=p;
}
void display(int i)
{
int j;
for(j=0;j<=i;j++)
printf("%d",b[j]);
}
void main()
{
int i,j;
clrscr();
i=0;
while(i<50)
{
scanf("%d",&a[i]);

if(a[i]==0)
{ zero(a[i],i);
count++;
}
else if(a[i]==1)
{ b[count]=a[i];
count++;
}
else
break;

printf("\t");
display(i);
printf("\n");
i++;

}
getch();
exit (1);
}
}
}
}

- Rajat January 23, 2014 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 votes

Here i am using array of 50. It can be changed as require.
And this code giving output in next line. Is this correct?

- Rajat January 23, 2014 | Flag
Comment hidden because of low score. Click to expand.
0
of 0 vote

#include <iostream>

using namespace std;

int main() {
    int c1=0, c0=0;
    char in;
    while(1){
        cin>>in;
        if(in=='1') c1++;
        else if(in=='0') c0++;
        else break;
        for(int i=c0; i>0; i--)
            cout<<0;
        for(int i=c1; i>0; i--)
            cout<<1;
        cout<<endl;
    }
    return 0;
}

- Crazy Tesla January 23, 2014 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

did without datastructure

while (true) {

            num = scanner.nextInt();

            if (num == 1) {
                count1++;
            }
            if (num == 0) {

                count0++;
            }

            for (int i = 0; i < count0; i++)
                System.out.print(""+0);

            for (int i = 0; i < count1; i++)
                System.out.print(""+1);
            System.out.println("");
        }

- Anonymous January 27, 2014 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

static String s ="";

public static void main(String args[])
{
Scanner in = new Scanner(System.in);
while (in.hasNext())
{
String str = in.nextLine();
if(str.equals("1") || str.equals("0"))
{
String s1 = testmethod(str);
System.out.println("s= "+s1);
}
else
return; // break; can also be used here.

}
}

public static String testmethod(String args)
{

if(args.equals("0"))
{
s = args+s;

}
else if(args.equals("1"))
{
s = s+args;
}

return s;
}

- pal March 03, 2014 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 votes

What is scanner class in this program? I did not find this in java.

- Abc September 25, 2014 | Flag
Comment hidden because of low score. Click to expand.
0
of 0 vote

#!/usr/bin/python

import os
import sys

numString = ''

while True:

	num = int(raw_input())

	if num == 1:
		numString += '1'

	elif num == 0:
		numString = '0' + numString

	print str(num)+' '+numString

- SBhatia November 23, 2017 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

In python:

while True:
    x=(input("Enter the numbers to append:"))
    if x=='q':
        break
    result=""
    for i in x:
        if i is '1':
            out.append(i)
        elif i is '0':
            out.insert(-len(out),i)
    result=(''.join(out))
    print (result)

- jagannathans92 March 02, 2018 | Flag Reply


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