Linkedin Interview Question for Software Engineers


Country: United States
Interview Type: In-Person




Comment hidden because of low score. Click to expand.
2
of 2 vote

Solution to Closest K Nodes

vector<int> closestKValues(TreeNode* root, double target, int k) {
        vector<int> res;
        inorder(root, target, k, res);
        return res;
    }
    void inorder(TreeNode *root, double target, int k, vector<int> &res) {
        if (!root) return;
        inorder(root->left, target, k, res);
        if (res.size() < k) res.push_back(root->val);
        else if (abs(root->val - target) < abs(res[0] - target)) {
            res.erase(res.begin());
            res.push_back(root->val);
        } else return;
        inorder(root->right, target, k, res);
    }

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- aonecoding August 30, 2017 | Flag Reply
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0
of 0 vote

II nested list sum

t=[]
def flatten(l):
  for i in l:
    print(type(i),i)
    if type(i)!=list:
      t.append(i)
    else:
      flatten(i)
  return t

- Anonymous October 22, 2017 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

Java Version:

public class KClosestNodes {
	
	public static void kClosestNodes(BinaryTreeNode root, int target, int k, Deque<Integer> q){
		if(root == null)
			return;
		kClosestNodes(root.getLeft(), target, k, q);
		
		if(q.size() < k){
			q.addLast(root.getData());
		}else if(Math.abs(target - root.getData()) < Math.abs(target - q.peekFirst())){
			q.removeFirst();
			q.addLast(root.getData());
		}else{
			return;
		}
		kClosestNodes(root.getRight(), target, k, q);
	}
	
	public static List<Integer> kClosestNodes(BinaryTreeNode root, int target, int k){
		Deque<Integer> q = new LinkedList<Integer>();
		List<Integer> result = new ArrayList<>();
		
		kClosestNodes(root, target, k, q);
		
		while(!q.isEmpty()){
			result.add(q.removeFirst());
		}
		
		return result;
	}
	public static void main(String[] args) {
		BinaryTreeNode root = buildBST();
		int target = 21, k = 3;
		System.out.println(kClosestNodes(root, target, k));

	}
	
	public static BinaryTreeNode buildBST(){
		BinaryTreeNode node3 = new BinaryTreeNode(3);
		BinaryTreeNode node5 = new BinaryTreeNode(5);
		BinaryTreeNode node7 = new BinaryTreeNode(7);
		BinaryTreeNode node20 = new BinaryTreeNode(20);
		
		BinaryTreeNode node6 = new BinaryTreeNode(6);
		node6.setLeft(node5);
		node6.setRight(node7);
		
		BinaryTreeNode node22 = new BinaryTreeNode(22);
		node22.setRight(node20);
		
		BinaryTreeNode node4 = new BinaryTreeNode(4);
		node4.setLeft(node3);
		node4.setRight(node6);
		
		BinaryTreeNode node17 = new BinaryTreeNode(17);
		node17.setRight(node22);
		
		BinaryTreeNode root = new BinaryTreeNode(9);
		root.setLeft(node4);
		root.setRight(node17);
		
		return root;
	}
}

public class BinaryTreeNode {
	private int data;
	private BinaryTreeNode left;
	private BinaryTreeNode right;
	
	public BinaryTreeNode(int data){
		this.data = data;
		this.left = null;
		this.right = null;
	}
	
	public int getData(){
		return this.data;
	}
	
	public void setData(int data){
		this.data = data;
	}
	
	public BinaryTreeNode getLeft(){
		return this.left;
	}
	
	public void setLeft(BinaryTreeNode left){
		this.left = left;
	}
	
	public BinaryTreeNode getRight(){
		return this.right;
	}
	
	public void setRight(BinaryTreeNode right){
		this.right = right;
	}
}

- AJ July 05, 2018 | Flag Reply


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