Riot Gaming Interview Question for Software Engineers


Team: unknown
Country: United States
Interview Type: Phone Interview




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1
of 1 vote

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public static int divide(int dividend, int divisor) {
        //if(divisor == 0) throw new Exception();
        int sign = 1;
        //figure out the sign of the result
        if((dividend < 0 && divisor > 0)
                || (dividend > 0 && divisor < 0)) {
            sign = -1;
        }
        if(dividend < 0) dividend = -dividend;
        if(divisor < 0) divisor = -divisor;
        int n = 1; //get the range of result [n, 2n], where n is doubled every round
        while(dividend > (n << 1) * divisor) {
            n <<= 1;
        }
        //now it's known that the result is between [n, 2n]
        //so in the dividend has a sum of more than n and less than 2n divisors in total
        //to figure out exactly how many divisors sum up to the dividend,
        // break down the problem to result = n + divide(dividend - n * divisor, divisor)
        // next round the dividend becomes (dividend - n * divisor) with n added to the result.
        // proceed to figure out the range [x, 2x] of result for the new dividend, where x can be n/2, n/4, n/8...
        // whenever the x is found, add x to the result and deduce x * divisor from the dividend
        // util n is 0 or dividend is 0

        //If written in math, the formula looks like dividend = ([T/F]* n + [T/F]* n/2 + [T/F]* n/ 4 + [T/F]* n/ 8...) * divisor
        //The quotient will be ([T/F]* n + [T/F]* n/2 + [T/F]* n/ 4 + [T/F]* n/ 8...), [T/F] depends on (dividend - n * divisor) >= 0
        int result = 0;
        while(n > 0 && dividend > 0) {
            if(dividend - n * divisor >= 0) {
                dividend -= n * divisor;
                result += n;
            }
            n >>= 1;
        }
        return result * sign;
    }

- alisonlee659 February 15, 2018 | Flag Reply
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0
of 0 vote

1 // This is the text editor interface.
  2 // Anything you type or change here will be seen by the other person in real time.
  3 #include <stdio.h>
  4 #include <stdlib.h>
  5 #include <time.h>
  6 #include <assert.h>
  7
  8 int divide(int num, int div)
  9 {
 10     int result = 0;
 11     int multiplier = 1;
 12     int divMultiplier = 1;
 13
 14     if (num < 0)
 15         multiplier = -1;
 16
 17     int absNum = num * multiplier;
 18
 19     if (div < 0)
 20         divMultiplier = -1;
 21
 22     int absDiv = div * divMultiplier;
 23
 24     int lb = 0;
 25     int ub = absNum + 1;
 26
 27     for (;;)
 28     {
 29         int middle = lb + ((ub - lb) >> 1);
 30         int guessed = middle * absDiv;
 31
 32         int match = guessed == absNum || ((guessed < absNum) && (absNum - guessed) < absDiv);
 33         if (match)
 34         {
 35             result = middle;
 36             break;
 37         }
 38         else if (guessed < absNum)
 39         {
 40             lb = middle;
 41         }
 42         else
 43         {
 44             ub = middle;
 45         }
 46     }
 47
 48     result *= multiplier;
 49     result *= divMultiplier;
 50     return result;
 51 }
 52
 53
 54 int main(int agrc, char* argv[])
 55 {
 56     printf("-5 / 1 = %d\n", divide(-5,1));
 57     printf("10 / 9 = %d\n", divide(10,9));
 58     printf("-10 / 2 = %d\n", divide(-10,2));
 59     printf("-10 / 3 = %d\n", divide(-10,3));
 60     // printf("-5 / 0 = %d", divide(-5,0));
 61     printf("5 / -1 = %d\n", divide(5,-1));
 62     printf("10 / -11 = %d\n", divide(10,-11));
 63     printf("10 / -12 = %d\n", divide(10,-12));
 64     printf("10 / -21 = %d\n", divide(10,-21));
 65     printf("10 / -10 = %d\n", divide(10,-10));
 66     printf("0 / -1 = %d\n", divide(0,-1));
 67     printf("1 / 1 = %d\n", divide(1,1));
 68     printf("1 / 2 = %d\n", divide(1,2));
 69     printf("100 / 101 = %d\n", divide(100,101));
 70     printf("1000 / 1001 = %d\n", divide(1000,1001));
 71     printf("10000 / 10001 = %d\n", divide(10000,10001));
 72     printf("10001 / 10000 = %d\n", divide(10001,10000));
 73     printf("10001 / 9999 = %d\n", divide(10001,9999));
 74     return 0;
 75 }
 76

- godzilla February 14, 2018 | Flag Reply


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