Amazon Interview Question for SDE-3s


Country: United States
Interview Type: In-Person




Comment hidden because of low score. Click to expand.
0
of 0 vote

public static Node pointToNextHigherElement(Node head) {
        Stack<Node> stack = new Stack<Node>();
        Node current = head;
        Stack<Node> tempList = new Stack<>();
        while ( current != null){
            if (stack.isEmpty()) {
                current = fillStack(stack, current, tempList);
            } else {
                Node elementFromStack = stack.pop();
                if (elementFromStack.value > current.value) {
                    stack.push(elementFromStack);
                    current = fillStack(stack, current, tempList);
                } else {
                    tempList.add(elementFromStack);
                }
            }

        }

        while(!stack.isEmpty()) {
            Node temp = stack.pop();
            if (!stack.isEmpty()) {
                Node next = stack.peek();
                temp.random = next;
            }
        }

        return head;
    }

    private static Node fillStack(Stack<Node> stack, Node current, Stack<Node> tempList) {
        stack.push(current);
        while (!tempList.isEmpty()) {
           stack.push(tempList.pop());
        }
        current = current.next;
        return current;
    }

- Trutgeek September 06, 2017 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

Good catch. Added a temp stack to hold values lesser than the current node.

- Trutgeek September 06, 2017 | Flag Reply
Comment hidden because of low score. Click to expand.
-1
of 1 vote

Put all the nodes in a min-heap.Keep extracting the root and populating the random pointer with the next extracted root from heap.

Space: O(N)
Time : O(NLogN)

- koustav.adorable August 31, 2017 | Flag Reply
Comment hidden because of low score. Click to expand.
-1
of 1 vote

public static Node pointToNextHigherElement(Node head) {
        Stack<Node> stack = new Stack<Node>();
        Node current = head;
        stack.push(current);
        current = current.next;
        while ( current != null){
            Node elementFromStack = stack.pop();
            if (elementFromStack.value > current.value) {
                stack.push(elementFromStack);
                stack.push(current);
            } else {
                stack.push(current);
                stack.push(elementFromStack);
            }
            current = current.next;
        }

        while(!stack.isEmpty()) {
            Node temp = stack.pop();
            if (!stack.isEmpty()) {
                Node next = stack.peek();
                temp.random = next;
            }
        }

        return head;
    }

- Trutgeek September 06, 2017 | Flag Reply
Comment hidden because of low score. Click to expand.
-1
of 1 vote

@Trutgeek, does it work for 2->4->3->1->8 ?

- koustav.adorable September 06, 2017 | Flag Reply


Add a Comment
Name:

Writing Code? Surround your code with {{{ and }}} to preserve whitespace.

Books

is a comprehensive book on getting a job at a top tech company, while focuses on dev interviews and does this for PMs.

Learn More

Videos

CareerCup's interview videos give you a real-life look at technical interviews. In these unscripted videos, watch how other candidates handle tough questions and how the interviewer thinks about their performance.

Learn More

Resume Review

Most engineers make critical mistakes on their resumes -- we can fix your resume with our custom resume review service. And, we use fellow engineers as our resume reviewers, so you can be sure that we "get" what you're saying.

Learn More

Mock Interviews

Our Mock Interviews will be conducted "in character" just like a real interview, and can focus on whatever topics you want. All our interviewers have worked for Microsoft, Google or Amazon, you know you'll get a true-to-life experience.

Learn More