Google Interview Question for Software Engineer / Developers

Country: Berling
Interview Type: Phone Interview

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The idea is to first find all the bin cells, and add then to a queue. You can then do a flood fill for every iteration through the queue where you add the neighbours of each cell to said queue as you go. See Python implementation below (assumes by 'distance' you meant manhattan distance):

from collections import deque

def get_dist_to_bin(M: list[list[int]]) -> D list[list[int]]:
	r, c = len(M), len(M[0])  # row, cols
	bins = deque()

	for i in range(r):
		for j in range(c):
			if M[i][j]:

			if    i and M[i-1][j]: dq.append( (i,j) )
			elif j and M[i][j-1]: dq.append( (i,j) )
			elif i<r-1 and M[i+1][j]: dq.append( (i,j) )
			elif j<c-1 and M[i][j+1]: dq.append( (i,j) )

	D = [[0]*c for _ in range(r)]  #initialize output

	curr_dist = 0
	curr_cnt = len(bins)
	while bins:
		i, j = dq.popleft()
		D[i, j] = curr_dist
		curr_cnt  -= 1

		if    i and not D[i-1][j]: dq.append( (i-1,j) )
		elif j and not D[i][j-1]: dq.append( (i,j-1) )
		elif i<r-1 and not D[i+1][j]: dq.append( (i+1,j) )
		elif j<c-1 and not D[i][j+1]: dq.append( (i,j+1) )
		if not curr_cnt: #finishes layer
			curr_dist += 1
			curr_cnt = len(bins)

	return D

- Anonymous December 03, 2021 | Flag Reply

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