Apple Interview Question for Software Engineer / Developers


Country: United States
Interview Type: In-Person




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0
of 0 vote

Does this make sense?

int square(int num)
	{
		int result = 0;

		int n = (num > 0) ? num : -num;

		for(int i = 0; i < n; ++i)
		{
			result += n;
		}

		return (num % 2 == 0) ? result : -result;
	}

- newbiev2 August 30, 2014 | Flag Reply
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of 0 votes

sorry, the return clause should be
return (num % 2 == 1 && num < 0) ? -result : result;

- Anonymous August 30, 2014 | Flag
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of 0 votes

Why is the last sentence judge whether num%2==1&&num<0? How could it return negative number? Can you give example?

- Why does this solution has possible negative result? January 13, 2015 | Flag
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of 0 vote

See this duplicate where a better solution has been posted: /question?id=5748016728244224

- Anonymous August 30, 2014 | Flag Reply
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0
of 0 vote

int square(int num)
{
int i,result=0;
for(i=0;i<num;i++)
{
result=result+num;
}
return result;
}

- Anonymous August 30, 2014 | Flag Reply
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of 0 vote

Sum of Odd numbers
1*1 = 1 // 1
2*2 = 4 // 1+3
3*3 = 9 // 1+3+5
4*4 =16// 1+3+5+7

and so on

- Abhay August 31, 2014 | Flag Reply
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0
of 0 votes

clearly says without using "*"

- Anonymous January 22, 2015 | Flag
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0
of 0 vote

Here is the approach to do in n/2 loop for a num 'n':

int square(int num)
{
int i,x,sum=0;
x = num/2;
for (i=0;i<x;i++)
{
sum = sum+num;
}
sum = sum+sum;
if(num%2)
     sum=sum+num;

return sum;
}

- Surya Rudra September 02, 2014 | Flag Reply
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of 0 vote

int Square(int num)
{
int counter = 0;
int val = num;
int sum = 0;

while(val > 0)
{
if(val & 1 == 1)
{
sum += num << counter;
}
counter++;
val >>= 1;
}

return sum;
}

- Anonymous October 06, 2014 | Flag Reply
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of 0 vote

public class App {

public static void main(String[] args) {

Scanner scanner = new Scanner(System.in);
System.out.println("Enter the number to find its square: ");
int num = scanner.nextInt();
scanner.close();
int squaredVal = 0;
for(int i=0; i<Math.abs(num); i++){
squaredVal = squaredVal + num;
}
System.out.println("Squared value is " + Math.abs(squaredVal));

}

}

- Anonymous November 24, 2015 | Flag Reply
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of 0 vote

public class App {

	/**
	 * @param args
	 */
	public static void main(String[] args) {

		Scanner scanner = new Scanner(System.in);
		System.out.println("Enter the number to find its square: ");
		int num = scanner.nextInt();
		scanner.close();
		int squaredVal = 0;
		for(int i=0; i<Math.abs(num); i++){
			squaredVal = squaredVal + num;
		}
		System.out.println("Squared value is " + Math.abs(squaredVal));
		
	}

}

- Anonymous November 24, 2015 | Flag Reply
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0
of 0 vote

and
public class App {

	/**
	 * @param args
	 */
	public static void main(String[] args) {

		Scanner scanner = new Scanner(System.in);
		System.out.println("Enter the number to find its square: ");
		int num = scanner.nextInt();
		scanner.close();
		int squaredVal = 0;
		for(int i=0; i<Math.abs(num); i++){
			squaredVal = squaredVal + num;
		}
		System.out.println("Squared value is " + Math.abs(squaredVal));
		
	}

}

- Anonymous November 24, 2015 | Flag Reply
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0
of 0 vote

public class App {

	/**
	 * @param args
	 */
	public static void main(String[] args) {

		Scanner scanner = new Scanner(System.in);
		System.out.println("Enter the number to find its square: ");
		int num = scanner.nextInt();
		scanner.close();
		int squaredVal = 0;
		for(int i=0; i<Math.abs(num); i++){
			squaredVal = squaredVal + num;
		}
		System.out.println("Squared value is " + Math.abs(squaredVal));
		
	}

}

- Anonymous November 24, 2015 | Flag Reply
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0
of 0 vote

public class App {

	/**
	 * @param args
	 */
	public static void main(String[] args) {

		Scanner scanner = new Scanner(System.in);
		System.out.println("Enter the number to find its square: ");
		int num = scanner.nextInt();
		scanner.close();
		int squaredVal = 0;
		for(int i=0; i<Math.abs(num); i++){
			squaredVal = squaredVal + num;
		}
		System.out.println("Squared value is " + Math.abs(squaredVal));
		
	}

}

- Anonymous November 24, 2015 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

public class App {

	/**
	 * @param args
	 */
	public static void main(String[] args) {

		Scanner scanner = new Scanner(System.in);
		System.out.println("Enter the number to find its square: ");
		int num = scanner.nextInt();
		scanner.close();
		int squaredVal = 0;
		for(int i=0; i<Math.abs(num); i++){
			squaredVal = squaredVal + num;
		}
		System.out.println("Squared value is " + Math.abs(squaredVal));
		
	}

}

- Anonymous November 24, 2015 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

public class App {

	/**
	 * @param args
	 */
	public static void main(String[] args) {

		Scanner scanner = new Scanner(System.in);
		System.out.println("Enter the number to find its square: ");
		int num = scanner.nextInt();
		scanner.close();
		int squaredVal = 0;
		for(int i=0; i<Math.abs(num); i++){
			squaredVal = squaredVal + num;
		}
		System.out.println("Squared value is " + Math.abs(squaredVal));
		
	}

}

- Anonymous November 24, 2015 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

Scanner scanner = new Scanner(System.in);
		System.out.println("Enter the number to find its square: ");
		int num = scanner.nextInt();
		scanner.close();
		int squaredVal = 0;
		for(int i=0; i<Math.abs(num); i++){
			squaredVal = squaredVal + num;
		}
		System.out.println("Squared value is " + Math.abs(squaredVal));

- Anonymous November 24, 2015 | Flag Reply
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0
of 0 vote

Any number can be expressed as sum of powers of 2.
n = 2**k + 2**l + ...
using that principle square(n) = n*(2**k) + n*(2**l) + ...
=(n << k) + (n<<l) + ...
code below

int getsquareNoAsterisk (int n) {
		int sn= 0;		
		int pos = 0;
		int curN = n;
		while (curN != 0) {
			if ( (curN & 1) == 1 ) {
				// This number has 2**pos value so add it with mulitplied
                                // by same number using << operator
				sn += (n << pos);
			}
			curN >>= 1;
			pos++;
		}
		
		return sn;
	}

- Srinivasa Alamuru March 12, 2016 | Flag Reply


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