Google Interview Question
Software EngineersCountry: United States
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Since the numbers have to be unique, we need to store numbers we have already used.
- krbchd May 01, 2017Also all numbers from 0 and maxValue - should have equal probability of being chosen)
Idea is for each iteration i (i is from 0-count-1),
1> chose random number from 0 -- maxValue-i
2> look in Map<Integer,Integer> , if the number is already seen
3> If not seen, place number in map and also map it to(that is set the value) to maxValue-i and return the number
4> If seen, then get the mapper value for the number, add new entry using mapped value as key and maxValue-i as value, return mapped value
Space -O(count)
Time -O(count)