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Do you really have to write the code for this?
- Bala January 07, 2015It appears like a math problem to me.
Assuming, the current point is p, q, r, s (left, right, bottom and top) from the edges. The farthest the point can go is the bounding rectangle of width 2k and height 2k and current point will be at the center.
So, just create that bounding rectangle and see how many points are outside that array and how many are inside. This gives you the probability.
Correct me, if I am wrong.