Uber Interview Question for Software Engineers


Country: United States
Interview Type: Phone Interview




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of 0 vote

def subset_sum_1(arr, target, partial=[], cur_sum=0):
    if cur_sum == target:
        yield partial
    if cur_sum >= target:
        return
    for i, n in enumerate(arr):
        remaining = arr[i + 1:]
        yield from subset_sum_1(remaining, target, partial + [n], cur_sum + n)

- Anonymous May 14, 2019 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

def subset_sum_1(arr, target, partial=[], cur_sum=0):
    if cur_sum == target:
        yield partial
    if cur_sum >= target:
        return
    for i, n in enumerate(arr):
        remaining = arr[i + 1:]
        yield from subset_sum_1(remaining, target, partial + [n], cur_sum + n)

- Mehdi May 14, 2019 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

One of the most efficient solutions to the above problem could be to use an
1. unordered set in c++.
2. push all the array elements into it.
3. now, one by one pick the elements from the array and calculate the difference between the total sum and the array element and find for the result in the set, if found push the set into the vector, and repeat this step till all the array elements have been processed and then, finally return the vector, which will be you final solution.
Thanks

- swapnilkant11 May 21, 2019 | Flag Reply


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