Facebook Interview Question


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1
of 1 vote

def get_tournament_winner(games_played):
    return (set([player[0] for player in games_played]) -  # O(N)
    set([win for winns in games_played for win in winns[1]]) ) # + O(N)

def test():
    input1 = [(1, [3,5,8,9]), (2, [1, 4, 6]), (3, [4, 9]), (4, [8])]
    winner = get_tournament_winner(input1)
    if winner != {2}:
        print(f"Test failed {winner}")
    else: 
        print("Test ok")

if __name__ == "__main__":
    test()

- yp November 25, 2021 | Flag Reply
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0
of 0 vote

P1>P2 and P2>P3 implies P1>P3
The first question is basically finding the max in an array. First compare between P1 and P2, store the bigger one and then match the result with P3. This process goes on till PN.

The second question is basically sorting the players. This is merge sort where the results of the pairwise matches determine which element is larger.

- Pratik October 05, 2021 | Flag Reply
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0
of 0 vote

int x

- Anonymous October 13, 2021 | Flag Reply
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0
of 0 vote

what was the input other than N?

- Anonymous October 27, 2021 | Flag Reply
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0
of 0 vote

What was the inputs other than N?

- Anirban October 27, 2021 | Flag Reply
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0
of 0 vote

// players: [0, n-1]
// w[0] wins w[1]
func Question1(n int, wins [][]int) int {
	// Two iteration, but strictly O(1) space
	var loser int
	for _, w := range wins {
		loser = w[1]
		// mark loser's index using negative value
		wins[loser][0] = math.MinInt32 + abs(wins[loser][0])
	}

	for i := 0; i < n; i++ {
		// winner never loses
		if wins[i][0] > 0 {
			return i
		}
	}
	return -1
}
func Question2(n int, wins [][]int) []int {
	// topological sort
	// O(n) time, O(n) space
	games := make(map[int][]int)
	ans, degrees := make([]int, n), make([]int, n)
	for _, w := range wins {
		games[w[1]] = append(games[w[1]], w[0])
		degrees[w[0]]++
	}
	// there should always be all-game losers, otherwise the deadlock occurs
	var queue []int
	for i, in := range degrees {
		if in == 0 {
			queue = append(queue, i)
		}
	}

	for len(queue) > 0 {
		size := len(queue)
		for i := 0; i < size; i++ {
			cur := queue[i]
			n--
			ans[n] = queue[i]
			for _, winner := range games[cur] {
				degrees[winner]--
				if degrees[winner] == 0 {
					queue = append(queue, winner)
				}
			}
		}
		queue = queue[size:]
	}
	return ans
}

- SM2LiWenCheng February 18, 2022 | Flag Reply
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0
of 0 vote

def find_tournament_winner(matches):
winner = None

for match in matches:
player1, player2 = match

if winner is None:
winner = player1

if winner == player1:
winner = player1
elif winner == player2:
winner = player2

return winner

# Example usage:
matches = [("P1", "P2"), ("P2", "P3"), ("P3", "P1"), ("P4", "P1")]
winner = find_tournament_winner(matches)
print("Winner of the tournament:", winner)

- PytZ November 25, 2023 | Flag Reply
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0
of 0 vote

def find_tournament_winner(matches):
    winner = None

    for match in matches:
        player1, player2 = match

        if winner is None:
            winner = player1

        if winner == player1:
            winner = player1
        elif winner == player2:
            winner = player2

    return winner

# Example usage:
matches = [("P1", "P2"), ("P2", "P3"), ("P3", "P1"), ("P4", "P1")]
winner = find_tournament_winner(matches)
print("Winner of the tournament:", winner)

- PythnZ November 25, 2023 | Flag Reply


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