Hewlett Packard Interview Question Tech Leads
Country: India
Interview Type: In-Person
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Hi, I think following code serves the purpose:
char * strcpy(char * target, const char * source) { char * destination = target; while ((*destination++ = *source++) != 0) ; return (destination); }Function parameters include source and target, both pointers to char or char array. source remains unchanged while processing so it is declared as const.
- soni.komal712 August 06, 2015It returns char * therefore it can be used directly in printf() like functions.
Yes it has been assumed that destination string is large enough and initialized, else there would be foloowing problems:
-->It might be pointing at memory you don't have access to, in which case it causes a segmentation fault and crashes your program
--> It might be pointing at real data, and if you don't know what it's pointing to, you're causing unpredictable (and very hard to debug) changes to your data.
-->You have no way of knowing if it's been initialized or not - because how do you tell the difference between a valid address and the address that happened to be there when you declared the pointer?