Interview Question


Country: United States
Interview Type: Written Test




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This is a problem to solve the complexity of an recursive algorithm.

I can be solved using the Master Theorem


for the complexity: T(n)=2T(n/2)+n

the general expression is T(n)=aT(n/b)+f(n), where f(n)=Theta(n^c*log^k n)

That means:
a=2,b=2
f(n)=Theta(n^1*log^0n)
c=1, k=0

log_a (b)= log_2 (2)=1 and at the same time c=1

That means it is case 2 of the Master theorem, then
T(n)=Theta(n^c* log_k+1(n))=Theta(n^1 * log_0_1 (n))=Theta(n*log(n)).

This is for example merge sort

- Anonymous October 15, 2014 | Flag Reply


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