Amazon Interview Question for SDE1s


Country: India
Interview Type: In-Person




Comment hidden because of low score. Click to expand.
2
of 2 vote

Answer is stack. Push and Pop is O(1). For find_min, you can maintain a seperate stack which stores the min element so far and you can pop the element from this stack if the element is popped from the main stack..

- arsragavan March 05, 2014 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

class MinStack <T> {
   
public push(T val) {
    m_data.push(val);
    if (val > m_mins.top()) {
        m_mins.push(m_mins.top());
    } else {
        m_mins.push(val);
    }
}
  
public T pop() {
    m_mins.pop();
    return m_data.pop();
}

public T min() {
    return m_mins.top();
}
   
private Stack<T> m_data;
private Stack<T> m_mins;
}

- Anonymous March 06, 2014 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 votes

In pop() what about the value returned by m_mins.pop(), you aren't handling it?

- gabbar March 09, 2014 | Flag
Comment hidden because of low score. Click to expand.
-1
of 3 vote

GOOGLE IT!!!

- ARE YOU STUPID March 05, 2014 | Flag Reply


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