Interview Question for Software Engineers

Country: United States

Comment hidden because of low score. Click to expand.
of 0 vote

#include <stdio.h>
#include <stdlib.h>
#include <iostream>
#include <math.h>

using namespace std;

class LineSeg {
    double x;
    double y;
    double z;
    double l;
    LineSeg(double X,double Y, double Z, double L){
        x = X;
        y = Y;
        z = Z;
        l = L;

class Circle {

    double centerX;
    double centerY;
    double centerZ;
    double radius;
    double normalX;
    double normalY;
    double normalZ;
    Circle(double X, double Y, double Z,double R, double nx, double ny, double nz) {
        centerX = X;
        centerY = Y;
        centerZ = Z;
        radius = R;
        normalX = nx;
        normalY = ny;
        normalZ = nz;

Circle * Configuration(LineSeg * L0, LineSeg * L1 ){
    double dx = L0->x - L1->x;
    double dy = L0->y - L1->y;
    double dz = L0->z - L1->z;
    double distance = sqrt( dx*dx + dy*dy + dz*dz);
    //cosine theorem
    double cos_of_L0_axis = (L0->l * L0->l + distance*distance - L1->l * L1->l )/ (2 * L0->l * distance );
    double centerDis_from_L0 = cos_of_L0_axis * L0->l;
    double sin_of_Lo_axis = sqrt(1 - cos_of_L0_axis * cos_of_L0_axis);
    double radius_of_circle = sin_of_Lo_axis * L0->l;
    //parameterized expression
    double centerx = L0->x + dx * (centerDis_from_L0 / distance);
    double centery = L0->y + dy * (centerDis_from_L0 / distance);
    double centerz = L0->z + dz * (centerDis_from_L0 / distance);
    if (distance > L0->l + L1->l) {
        cout << "two points are too far from each other"<<endl;
        return nullptr;

    double dis = 0;
    dis = L0->l - L1->l;
    if(dis < 0){
        dis = -dis;
    if (distance < dis) {
        cout<< "two points are too closed to each other" << endl;
        return nullptr;
    return new Circle( centerx, centery, centerz, radius_of_circle, dx,dy,dz);

- albertchenyu February 24, 2015 | Flag Reply
Comment hidden because of low score. Click to expand.
of 2 vote

You know all three sides of the triangle, so you can use law of sines to find neede angle and then calculate required position.

- Yola February 11, 2015 | Flag Reply

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