CareerCup

bool isEven(int num) {
	    if (num & 1) {
	        return false;
	    }
	    else {
	        return true;
	    }
	}

bool isEven(int num) {
	    if (num & 1) {
	        return false;
	    }
	    else {
	        return true;
	    }
	}

bool isEven(int num) {
	    if (num & 1) {
	        return false;
	    }
	    else {
	        return true;
	    }
	}

bool isEven(int num) {
if (num & 1) {
return false;
}
else {
return true;
}
}

bool isEven(int num)
{
int isOddOrEven = num & 1;
if(isOddOrEven == 1)
return false; // For Odd we return false
else
return true;// True for even
}

bool isEven(int num)

int isOddOrEven = num & 1;
     if ( isOddOrEven == 1)
           return false; // for odd it's false
     else
         return true;

function isEven(num) { 
     return num % 2 === 0;
   }

boolean isEven(int num){
return num % 2==0;
}

Little modification in the question:-
Write a function which accepts an integer and prints if the the integer is even or odd.

Restrictions on your code:-
1. Code should not use any kind of condition checks(such as if..else, ?:[i.e. ternary operators],macros in any form).
2. Operators for checking equality like "==" should not be used.
3. Looping in any form should not be used.
4. No bitwise operators should be used.

def f(val):
  print ("even", "odd")[val % 2]