Adobe Interview Question for Java Developers


Country: India
Interview Type: Written Test




Comment hidden because of low score. Click to expand.
0
of 0 vote

looks like interview is expecting regular expression not coding style. Any way your program works.

- sbhargavs August 11, 2018 | Flag Reply
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0
of 0 vote

import java.util.Scanner;

public class Home {

public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
String s = scanner.next();
String[] good_words = {"papa", "book", "home", "cars", "jolly", "sugar", "friend", "mother", "father", "bloomiest"};
String[] bad_words = {"ache", "slow", "torn", "slum", "boom", "rival", "wrong", "cholera", "revenge", "arrogant"};
for(String str : good_words){
if(str.equalsIgnoreCase(s)){
System.out.println("GOOD");
}
}for(String str : bad_words){
if(str.equalsIgnoreCase(s)){
System.out.println("BAD");
}
}
}

}

- Anonymous October 11, 2018 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

import java.util.Scanner;

public class Home {

	public static void main(String[] args) {
		Scanner scanner = new Scanner(System.in);
		String s = scanner.next();
		 String[] good_words = {"papa", "book", "home", "cars", "jolly", "sugar", "friend", "mother", "father", "bloomiest"};
	     String[] bad_words = {"ache", "slow", "torn", "slum", "boom", "rival", "wrong", "cholera", "revenge", "arrogant"};
	     for(String str : good_words){
	    	 if(str.equalsIgnoreCase(s)){
	    		 System.out.println("GOOD");
	    	 }
	     }for(String str : bad_words){
	    	 if(str.equalsIgnoreCase(s)){
	    		 System.out.println("BAD");
	    	 }
	     }
	}

}

- Mohini yadav October 11, 2018 | Flag Reply
Comment hidden because of low score. Click to expand.
-1
of 1 vote

I tried to solve that quiz.. But I'm not sure about it.
So, please, check it out:

Scanner scanner = new Scanner(System.in);
        String[] good_words = {"papa", "book", "home", "cars", "jolly", "sugar", "friend", "mother", "father", "bloomiest"};
        String[] bad_words = {"ache", "slow", "torn", "slum", "boom", "rival", "wrong", "cholera", "revenge", "arrogant"};
        String input_data = scanner.nextLine();
        int good_indicator = 0;
        int bad_indicator = 0;
        for (int i = 0; i<good_words.length; i++){
            if (input_data.equals(good_words[i])){
                good_indicator++;
            }
        }if (good_indicator!=0) {
            System.out.println("Good");
        }else{
            for (int i = 0; i<bad_words.length;i++){
                if (input_data.equals(bad_words[i])){
                    bad_indicator++;
                }
            }
            if (bad_indicator!=0){
                System.out.println("Bad");
            }
        }

- xidonett August 07, 2018 | Flag Reply


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