## CGI-AMS Interview Question

Software Engineer / Developers**Country:**United States

**Interview Type:**Written Test

Take "n" as the limit for "Rs. 300".

u1 = number of calls by person 1 = n + k1.

u2 = number of calls by person 2 = n + k2.

R = Rate in Rs/call

p1 = price paid by person 1 = 425 = 300 + k1 * R => k1R = 125

p2 = price paid by person 2 = 925 = 300 + k2 * R => k2R = 625

Result1: k2 = 5 k1 and 6k1 * R = 750

Total calls = 1400 ==> n + k1 + n + k2 = 2n + 6k1 = 1400

Result2: n + 3k1 = 700

u = calls by one person = 2n + 6k1 = 1400

p = price by one person = 300 + (n + 6k1) * R = 1550 ==> n * R = 1550 - 750 - 300 = 500

Result3: n * R = 500

Result1 & Result 3 => Result 4: k1 / n = 125 / 500

Result2 & Result4 => (1 + 125 / 500 * 3) * n = 700 ==> n = 500

N is the number of telephone calls allowed for a lumpsum charge of Rs.300.

R is the rate beyond that.

You would get equations like the following.

2N+(425-300)/R+(925-300)/R=1400

(1400-N)R+300=1550

You can easily get NR and R from the above equations and you would get N eventually.

N = 400

n is the number of telephone calls allowed for a lumpsum charge of rs.300.

r is the rate beyond that.

You would get equations like the following.

2n+125/r+625/r=1400

2nr+ 125+625 = 1400r

2nr + 750-1400r=0 --1

(1400-n)r=1250

1400r -nr -1250 =0 --2

now multiply 2 by 2 and add both 1 nd 2

1400r - 1750 =0

r = 1750/1400 = 1.25

so n = 400

Take "n" as the limit for "Rs. 300".

- goutambesu November 28, 2013Case1(When one is using):

per call rate after crossing the limit(i.e n)=(1550-300)/(1400-n)

Case2(When only both are using)

per call rate after crossing the limit(i.e n)=((425+925)-(300*2))/(1400-2n)

so 1250/(1400-n)=750/(1400-2n)

. n=400